Is xy > ab ?
(1) b/x > y/a
(2) (ab)^2 > (xy)^2
Kudos for a correct solution.
1) b/x > y/a
variable involved and we dont know the sign . therefore cant multiply . not sufficient.
2)(ab)^2 > (xy)^2
since both side are raised to the power 2 .
both ab and xy , can be positive or negative .
(ab)^2 > (xy)^2
let ab =2 and xy = 1
then (ab)^2 > (xy)^2 satisfied
but
Is xy > ab ? No
let ab = -1 and xy =1/2
then (ab)^2 > (xy)^2 satisfied
but
Is xy > ab ? yes
st .2 is not sufficient
together both 1 and 2 not sufficient . Since dont give any information that is helpful to solve the question
Hence E
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