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Is (-y)/2 > y^2 ?

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Is (-y)/2 > y^2 ? [#permalink]

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New post 03 Mar 2015, 06:27
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A
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C
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Difficulty:

  65% (hard)

Question Stats:

59% (01:20) correct 41% (01:29) wrong based on 227 sessions

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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 03 Mar 2015, 07:25
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Y squ =1/25
y=1/5 or -1/5.
If Y =1/5 then -y/2>ysquare

-1/10<1/25 not sufficient.

y=-1/5 then 1/10>1/25.
Option 1 is insufficient.


2 Mod y = -y => y=-ve

so put values y=-1 then 1/2<1
y=-1/2 then 1/4=1/4

y=-1/3 then 1/6>1/9

y=-1/4 then 1/8>1/16.

from y>=-1/3.

Combine 1 and 2 y=-1/5. so Option is C sufficient.

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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 05 Apr 2015, 14:20
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Hi All,

This DS question involves a bit of math and a bit of Number Properties; by TESTing VALUES, you can prove what the correct answer is.

We're ask if (-Y)/2 is greater than Y^2. This is a YES/NO question.

Fact 1: Y^2 = 1/25

Here, we're dealing with a straight-forward equation with two solutions: 1/5 and -1/5. We still have to make sure that we're answering the question that's ASKED though:

IF....
Y = 1/5
(-1/5)/2 = -1/10
-1/10 is NOT greater than 1/25 so the answer to the question is NO

IF....
Y = -1/5
(-(-1/5))/2 = 1/10
1/10 IS greater than 1/25 so the answer to the question is YES
Fact 1 is INSUFFICIENT

Fact 2: |Y| = -Y

This Fact tell us that Y CANNOT be positive. It can be 0 or ANY negative number though.

IF....
Y = -1/5
(-(-1/5))/2 = 1/10
1/10 IS greater than 1/25 so the answer to the question is YES

IF...
Y = 0
0/2 is NOT greater than 0 so the answer to the question is NO
Fact 2 is INSUFFICIENT

Combined, we know....
Y = 1/5 or -1/5
Y is 0 or ANY negative

There's only 1 value that fits both Facts: -1/5....so the answer to the question is ALWAYS YES.
Combined, SUFFICIENT

Final Answer:
[Reveal] Spoiler:
C


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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 24 May 2016, 08:04
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EMPOWERgmatRichC wrote:
Hi All,

This DS question involves a bit of math and a bit of Number Properties; by TESTing VALUES, you can prove what the correct answer is.

We're ask if (-Y)/2 is greater than Y^2. This is a YES/NO question.

Fact 1: Y^2 = 1/25

Here, we're dealing with a straight-forward equation with two solutions: 1/5 and -1/5. We still have to make sure that we're answering the question that's ASKED though:

IF....
Y = 1/5
(-1/5)/2 = -1/10
-1/10 is NOT greater than 1/25 so the answer to the question is NO

IF....
Y = -1/5
(-(-1/5))/2 = 1/10
1/10 IS greater than 1/25 so the answer to the question is YES
Fact 1 is INSUFFICIENT

Fact 2: |Y| = -Y

This Fact tell us that Y CANNOT be positive. It can be 0 or ANY negative number though.

IF....
Y = -1/5
(-(-1/5))/2 = 1/10
1/10 IS greater than 1/25 so the answer to the question is YES

IF...
Y = 0
0/2 is NOT greater than 0 so the answer to the question is NO
Fact 2 is INSUFFICIENT

Combined, we know....
Y = 1/5 or -1/5
Y is 0 or ANY negative

There's only 1 value that fits both Facts: -1/5....so the answer to the question is ALWAYS YES.
Combined, SUFFICIENT

Final Answer:
[Reveal] Spoiler:
C


GMAT assassins aren't born, they're made,
Rich


Missed the case that y could be zero. Good explanation :)
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Is (-y)/2 > y^2 ? [#permalink]

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New post 24 May 2016, 09:42
Hi spetznaz,

As a general rule, you should keep "0" in mind when working through every DS question that you face. Beyond the fact that it's a remarkably easy number to TEST, it's often a 'pattern-breaker' and helps to prove that a particular Fact is insufficient. The difference between the correct answer and any of the incorrect answers often comes down to the 'thoroughness' of your thinking; just a little more (focused) work will get you the correct answer.

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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 24 May 2016, 10:10
Bunuel wrote:
Is (-y)/2 > y^2 ?

(1) y^2 = 1/25
(2) |y| = -y


Kudos for a correct solution.


y^2 will always be +ve; hence for LHS to be greater than y^2, it should be +ve.
Also, it should fulfill two conditions:-

1) y should be -ve
2) y should be >-1/2 (because if y= -1/2 then LHS=RHS and if it is <-1/2 then LHS < RHS)

1st statement-
y^2= 1/25
y= 1/5 or -1/5

If its +1/5 then the does not hold good, but if it is -1/5 then yes. Insufficient.

2nd statement-
|y| = -y
That means y is -ve, but doesn't tell u sit y is >-1/2 Not sufficient

Combining statement 1 and 2, we get the answer that y=-1/5
Hence C is the answer
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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 25 May 2016, 02:57
If we modify the original condition and the question, we get 0>y^2+(y/2)?, 0>y(y+1/2)?. This leads to -1/2<y<0?. However, using 1) and 2), we get y=-1/5. The answer is yes and the conditions are sufficient. Hence, the correct answer is C.
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Re: Is (-y)/2 > y^2 ? [#permalink]

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New post 11 Oct 2016, 03:26
did algebraic

is -y/2>y^2? means y(2y+1)<0 means -1/2<y<0? So, that is the question

St1. y=+-1/5. Not Suff

St.2 y<0. Not Suff

St1+St2 means y=-1/5. Suff

C

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Re: Is (-y)/2 > y^2 ? [#permalink]

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Re: Is (-y)/2 > y^2 ?   [#permalink] 31 Oct 2017, 06:00
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