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05 Nov 2014, 08:28
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B
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Difficulty:
35%
(medium)
Question Stats:
69% (01:51) correct
31%
(01:54)
wrong
based on 185
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Tough and Tricky questions: Inequalities.
Is Y greater than 7/11?
(1) 1/5 < Y < 11/12
(2) 2/9 < Y < 8/13
Kudos for a correct solution.
revul
Joined: 07 Oct 2014
Last visit: 07 May 2016
Posts: 160
Given Kudos: 17
Schools: Duke '17 (M) Tuck '17 (D) Ross '17 (A) Darden '17 (A) Cambridge'16 (WD) Kenan-Flagler '17 (A)
GMAT 1: 710 Q48 V39
WE:Sales (Other)
Schools: Duke '17 (M) Tuck '17 (D) Ross '17 (A) Darden '17 (A) Cambridge'16 (WD) Kenan-Flagler '17 (A)
GMAT 1: 710 Q48 V39
Posts: 160
05 Nov 2014, 12:12
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(1) 1/5 < Y < 11/12
So Y is bigger than 1/5 and less than 11/12. so y could be 6/11 or 8/11 (eyeball given the numbers are easy). Therefore insufficient
(2) 2/9 < Y < 8/13
Actually have to do some math here. 2/9 is small enough not to worry about it, 8/13 vs. 7/11 isn't an easy eyeball:
7/11 and 8/13, workable numbers for common denom via multiplication: (7*13)/(13*11) vs. (8*11)/(13*11). Same denom therefore denom is irrelevant. Is 7*13 (70+21 = 91) bigger than 88? yes. So because 7/11 is bigger than Y's maximum range, Y is not greater than 7/11, SUFFICIENT
therefore B.
So Y is bigger than 1/5 and less than 11/12. so y could be 6/11 or 8/11 (eyeball given the numbers are easy). Therefore insufficient
(2) 2/9 < Y < 8/13
Actually have to do some math here. 2/9 is small enough not to worry about it, 8/13 vs. 7/11 isn't an easy eyeball:
7/11 and 8/13, workable numbers for common denom via multiplication: (7*13)/(13*11) vs. (8*11)/(13*11). Same denom therefore denom is irrelevant. Is 7*13 (70+21 = 91) bigger than 88? yes. So because 7/11 is bigger than Y's maximum range, Y is not greater than 7/11, SUFFICIENT
therefore B.
General Discussion
10 Nov 2014, 07:43
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Is Y greater than 7/11?
Y>0.7 approx
(1) 1/5 < Y < 11/12
max value for Y can be 11/12=0.9 approx
so here values for Y can be 0.2 -0.9
since values for Y can be both smaller and greater than 0.7
INSUFFICIENT.
(2) 2/9 < Y < 8/13
max value for Y can be 8/13=0.6
so here max value for Y is itself less than 0.7
it implies that Y is smaller than 7/11
SUFFICIENT.
Answer is B
Y>0.7 approx
(1) 1/5 < Y < 11/12
max value for Y can be 11/12=0.9 approx
so here values for Y can be 0.2 -0.9
since values for Y can be both smaller and greater than 0.7
INSUFFICIENT.
(2) 2/9 < Y < 8/13
max value for Y can be 8/13=0.6
so here max value for Y is itself less than 0.7
it implies that Y is smaller than 7/11
SUFFICIENT.
Answer is B
