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27 Feb 2017, 04:29
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
71% (01:23) correct
29%
(01:39)
wrong
based on 130
sessions
History
Date
Time
Result
Not Attempted Yet
27 Feb 2017, 08:33
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Bunuel
Is y – z < x – z?
(1) y lies between x and z.
(2) z < x < 0
(1) y lies between x and z.
(2) z < x < 0
Question : Is y – z < x – z?
Question : Is y < x ?
Statement 1: y lies between x and z.
y may be greater or smaller than x hence
NOT SUFFICIENT
Statement 2: z < x < 0
No mention of y hence
NOT SUFFICIENT
Combining the two statements
z < x < 0 and y is between x and z
i.e. z < y < x < 0
SUFFICIENT
Answer: Option C
Updated on: 22 Mar 2017, 07:24
Originally posted by BrentGMATPrepNow on 27 Feb 2017, 09:06.
Last edited by BrentGMATPrepNow on 22 Mar 2017, 07:24, edited 1 time in total.
Last edited by BrentGMATPrepNow on 22 Mar 2017, 07:24, edited 1 time in total.
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Bunuel
Is y – z < x – z?
(1) y lies between x and z.
(2) z < x < 0
(1) y lies between x and z.
(2) z < x < 0
Target question: Is y – z < x – z?
This is a good candidate for rephrasing the target question.
Take y – z < x – z and add z to both sides to get: y < x.
So,......
REPHRASED target question: Is y < x?
Statement 1: y lies between x and z.
BE CAREFUL, we cannot conclude that x < y < z, because it could also be the case that z < y < x
In both cases, y lies between x and z on the number line. These two possible scenarios yield different answers to the REPHRASED target question.
Case a: if x < y < z, then we can see that x < y.
Case b: if z < y < x, then we can see that y < x.
Since we cannot answer the REPHRASED target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: z < x < 0
There's no information about y.
So, there's no way to determine whether or not y < x
Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
Statement 1 tells us that EITHER x < y < z OR z < y < x
Statement 2 tells us that z < x, which RULES OUT the possibility that x < y < z
So, it MUST be the case that z < y < x, which means y < x
So, the answer to the REPHRASED target question is "YES. It IS the case that y < x"
Since we can answer the REPHRASED target question with certainty, the combined statements are SUFFICIENT
Answer: C
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