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27 May 2020, 07:06
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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72% (02:14) correct
28%
(02:48)
wrong
based on 151
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It is determined that 25 of every 100 men and 600 of every 1,000 women wear glasses. If the number of women in a particular room is four times more than that of men, calculate the probability of a person without glasses being randomly selected.
(A) 0.47
(B) 0.45
(C) 0.49
(D) 0.48
(E) 0.43
(A) 0.47
(B) 0.45
(C) 0.49
(D) 0.48
(E) 0.43
Updated on: 27 May 2020, 21:47
Originally posted by GMATinsight on 27 May 2020, 09:59.
Last edited by GMATinsight on 27 May 2020, 21:47, edited 1 time in total.
Last edited by GMATinsight on 27 May 2020, 21:47, edited 1 time in total.
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karan12345
Glass wearing Men = 25%
Glass wearing Women = 60%
Let, Men = 100 i.e. Women = 4*100 = 400
Men with glasses = 25% of 100 = 25 and
Women with glasses = 60% of 400 = 240
Total Members = 100+400 = 500
Total Members with glasses = 25+240 = 265
Total Members without glasses = 500-265 = 235
Required Probability = Without glasses people / Total people = 235/500 = 0.47
Answer: Option A
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27 May 2020, 10:58
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25 out if 100 men wear glass.
So, 0.25 out of 1 man ----(1)
And,
600 out of 1000 women wear Glass,
So, 0.6 out of 1 woman -----(2)
In a room there is 1 man : 4 women ratio.
Total chances of them wearing Glass is (0.6*4+0.25)/(4+1)
=> (2.4+0.25)/5
=> 2.65/5 = 0.53
Probability of them no wearing Glass is 1-favourable = 1-0.53 = 0.47
Answer is A
Posted from my mobile device
So, 0.25 out of 1 man ----(1)
And,
600 out of 1000 women wear Glass,
So, 0.6 out of 1 woman -----(2)
In a room there is 1 man : 4 women ratio.
Total chances of them wearing Glass is (0.6*4+0.25)/(4+1)
=> (2.4+0.25)/5
=> 2.65/5 = 0.53
Probability of them no wearing Glass is 1-favourable = 1-0.53 = 0.47
Answer is A
Posted from my mobile device
