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Updated on: 18 Jan 2016, 04:17
Originally posted by MathRevolution on 13 Jan 2016, 19:17.
Last edited by Bunuel on 18 Jan 2016, 04:17, edited 1 time in total.
Last edited by Bunuel on 18 Jan 2016, 04:17, edited 1 time in total.
Added the OA.
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
77% (02:23) correct
23%
(03:20)
wrong
based on 79
sessions
History
Date
Time
Result
Not Attempted Yet
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 360, 300, and 300 as the side’s lengths, what is the triangle’s area?
A. 34,200
B. 36,200
C. 38,200
D. 42,200
E. 43,200
*A solution will be posted in two days.
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 360, 300, and 300 as the side’s lengths, what is the triangle’s area?
A. 34,200
B. 36,200
C. 38,200
D. 42,200
E. 43,200
*A solution will be posted in two days.
13 Jan 2016, 20:52
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MathRevolution
Hi,
how can this Q be of 700+ difficulty..
Its not worth sub-600..
All values given, even formula given.. Just put values and get the answer
13 Jan 2016, 23:26
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MathRevolution
Point No. 1: GMAT Takers are not supposed to know about the well know Heron's formula√(p(p-a)(p-b)(p-c))
Point No. 2: This question doesn't require application of Heron's formula √(p(p-a)(p-b)(p-c))
Make an Isosceles triangle with two sides 300 and base 360
Drop Perpendicular on Base (dividing base into two halves of 180 each) and use Pythagorus theorem to calculate height = √((300^2)-(180^2)) = 240
Area of Triangle = (1/2)*360*240 = 43200
Answer: Option E
It is a 600 level question (in my opinion) as per GMAT standard
