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Bunuel

Tough and Tricky questions: Word Problems.



Janet is now 25 years younger than her mother Carol. If in 6 years Janet's age will be half Carol’s age, how old was Janet 5 years ago?

A. 10
B. 14
C. 16
D. 19
E. 25


Janet ................................... Carol

x .......................................... x+25 (Current Age)

x+6 ...................................... x+31 (After 6 yrs)

Given that \(\frac{1}{2} (x+31) = x+6\)

x = 19 = Current age of Janet

5 yrs ago Janet's age = 19-5 = 14

Answer = B
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Bunuel

Tough and Tricky questions: Word Problems.



Janet is now 25 years younger than her mother Carol. If in 6 years Janet's age will be half Carol’s age, how old was Janet 5 years ago?

A. 10
B. 14
C. 16
D. 19
E. 25

J=C-25

J+6=(C+6)/2
2J+12=C+6
C-2J=6
C-2(C-25)=6
C-2C+50=6
-C=-44
C=44
J=19

5 years ago, J was 14.

Answer B
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