Bunuel wrote:

Jennifer can buy watches at a price of B dollars per watch, which she marks up by a certain percentage before selling. If she makes a total profit of T by selling N watches, then in terms of B and T and N, what is the percent of the markup from her buy price to her sell price?

A. 100T/(NB)

B. TB/(100N)

C. 100TN/B

D. ((T/N) – B)/(100B)

E. 100(T – NB)/N

Let's say The price of each watch, i.e. B = 7,

Let's say Mark up = 400%==> 400% of 7 is 28, and the $7 watches are marked up $28,

then the selling price per watch = $35.

The profit per watch is $28, and so

if she sells N = 11 watches

Then Total profit, T = 28*11 = $308.

OK, now Substitute T = 308 = 11*28, N = 11, and B = 7, in options and hope to get 400 as our answer.

(A) 100T/(NB) = 100*11*28/(11*4) = 100*28/7 = 110*4 = 400 = works!(B) TB/(100N) = 11*28*7/(100*11) = 28*7/100 = doesn’t work!

(C) 100TN/B = 100*11*28*11/7 = 100*11*4*11 = doesn’t work!

(D) ((T/N) – B)/(100B) = [(11*28/11) – 7]/(7*100) = (28 – 7)/(7*100) = 21/(7*100) = 3/100 = doesn’t work

(E) 100(T – NB)/N = 100(11*28 – 11*7)/7 = 100*11*21/7 = 100*11*3 = doesn’t work!

Answer: Option

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