Jessica can text 85 words per minute, while Maurice can text 10 words per minute. An abridged English translation of Tolstoy’s War and Peace contains 410,400 words. Working together, how many days will it take Jessica and Maurice to text the entire abridged translation of War and Peace?

A. 0.3
B. 1.3
C. 3
D. 9
E. 11.3

Combined, they can text 95 words per minute.

So they will take 410,400 / 95 = 4320 mins to type the entire book

which is 4320/(60*24) days = 3 days
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Rate * Time = Work

Combined Rate = 85+10

95*Time = 41400

Time in Days = 41400/(95*60*24)

T=3

hi gradyf,

Not likely that you will see such intensive calculations..
But if you such a Q..

Combined speed 85+10=95 words/min..
so 410400 words in \(\frac{410400}{95*60*24}\) days..

Now see if choices can help you...
4104 is a multiple of 9 as 4+1+0+4 is multiple of 9.....
4104 is also a multiple of 19 as the Denominator 95 is a multiple of 19 and NONE of the choices have 19..
also 4104 is a multiple of 8 as LAST 3 digits 104 is multiple of 8....
when you multiply 9*19*8, you realize only another 3 is required to reach 4104...
so \(\frac{19*9*8*3*100}{19*5*60*8*3}=\frac{9*10*5*2}{5*3*2*10}=3\)

ofcourse still calculations are there but slightly lesser work
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Together they can text 85 + 10 = 95 words per minute, which means they can text 95 x 60 = 5,700 words per hour. Therefore, if we let x = the number of hours it takes for them to text the entire abridged translation of War and Peace, we have:

5,700x = 410,400

x = 410,400/5,700

x = 72 hours

Assuming they work 24 hours a day, it will take them 72/24 = 3 days to text the entire abridged translation of War and Peace.

Answer: C
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