Author 
Message 
TAGS:

Hide Tags

Senior Manager
Joined: 24 Feb 2008
Posts: 348
Schools: UCSD ($) , UCLA, USC ($), Stanford

Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
20 Apr 2008, 13:27
Question Stats:
71% (01:56) correct 29% (02:09) wrong based on 844 sessions
HideShow timer Statistics
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today? A. 51 B. 52 C. 53 D. 54 E. 55
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Chinese Democracy is misunderstood...at your nearest BestBuy.
Best AWA guide here: http://gmatclub.com/forum/howtoget60awamyguide64327.html




Math Expert
Joined: 02 Sep 2009
Posts: 49320

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
11 Apr 2014, 03:54




Senior Manager
Joined: 01 Feb 2005
Posts: 258

Re: PS: 4 birthdays
[#permalink]
Show Tags
21 Apr 2008, 17:01
Some time ago I read in Kaplan... that if a question has the phrase "Which of the following..." (verbal or Quant) try the answer choices from the bottom (from E up)... That's how I got in my very second choice (D) I got the answer without attempting the other 3... Just thought I'd share that piece of info... If u guys already know this... discard this message




Intern
Joined: 02 Apr 2008
Posts: 37

Re: PS: 4 birthdays
[#permalink]
Show Tags
20 Apr 2008, 14:10
Answer D
total x+x+1+x+2+x+3 total= 4x+6 birthdays at the same day, so total = integer 54 6 = 48, which is divisible by 4 so, x= 12 4*12 +6 = 54



VP
Joined: 10 Jun 2007
Posts: 1387

Re: PS: 4 birthdays
[#permalink]
Show Tags
20 Apr 2008, 19:02
chineseburned wrote: Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today? A. 51 B. 52 C. 53 D. 54 E. 55 D K = J + 2 K = L + 3 M = J + 1 Total = K + J + M + L = K + K  2 + K  2 + 1 + K  3 = 4K  6 I tried out all numbers and only 54 works as an integer of K. (54 + 6)/4 = K = integer The rest give fractions.



Current Student
Joined: 28 Dec 2004
Posts: 3268
Location: New York City
Schools: Wharton'11 HBS'12

Re: PS: 4 birthdays
[#permalink]
Show Tags
20 Apr 2008, 19:23
the way i did is very similar to Bkk's approach.. j=k2 k=L+3 m=1+J L=L j=L+1; M=L+2 total sum of ages= (L+1+L+2+L+3+L=4L+6 then i subtract 6 from all the answer choices..the resulting number should be divisible by 4.. 54 is the only one D it is..



Intern
Joined: 06 Aug 2007
Posts: 30
Location: Montreal

Re: PS: 4 birthdays
[#permalink]
Show Tags
21 Apr 2008, 12:16
I'd say 54 as well...
J= K2 = K2 K= L+3 = K L= K3 = K3 M= J+1 = K1
Then, I gave K=15 so 15+14+13+12= 54



SVP
Joined: 11 Mar 2008
Posts: 1615
Location: Southern California
Schools: Chicago (dinged), Tuck (November), Columbia (RD)

Re: PS: 4 birthdays
[#permalink]
Show Tags
21 Apr 2008, 15:51
D J = K  2 K = 3 + L M = 1 + J L = 12 K = 15 27 J = 13 40 M = 14 54
_________________
Check out the new Career Forum http://gmatclub.com/forum/133



SVP
Joined: 04 May 2006
Posts: 1736
Schools: CBS, Kellogg

Re: PS: 4 birthdays
[#permalink]
Show Tags
21 Apr 2008, 19:46
axl_oz wrote: Just thought I'd share that piece of info...
If u guys already know this... discard this message I have just be informed, thanks!
_________________
GMAT Club Premium Membership  big benefits and savings



Current Student
Joined: 28 Dec 2004
Posts: 3268
Location: New York City
Schools: Wharton'11 HBS'12

Re: PS: 4 birthdays
[#permalink]
Show Tags
21 May 2008, 13:16
i was just thinking..if you are in a tight spot and have to quickly think..maybe you have 3 questions left and only 1 minute left to do em..
you know that one of the girls is 2 years younger and one is 3 years older..
so then of the answer choice..1 of these choices must be divisble by 3..now look at 2..the answer choice has to be even..so 54 is the best choice..51 is close but its not divisible by 2..



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1834
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
11 Apr 2014, 01:24
Let present age of Kylie = x, then present ages of.... Joan = x2 Lillian = x3 Miriam = x1 Total age = x + x1 + x2 + x3 = 4x  6 Option A, C, E are odd, hence can be discarded 54 + 6 = 60 which is divisible by 4 Answer = D
_________________
Kindly press "+1 Kudos" to appreciate



Senior Manager
Joined: 25 Mar 2013
Posts: 256
Location: United States
Concentration: Entrepreneurship, Marketing
GPA: 3.5

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
11 Apr 2014, 08:27
My strategy is Word Problem ,By plugging in And forming the Equation k = x , J = x 2 , L = x  3 , M = x  2 + 1 So x+ x  2 + x 3 + x  2 + 1 = 4x  6 4x6 = Total By Using Options x = 15 So Total is 54
_________________
I welcome analysis on my posts and kudo +1 if helpful. It helps me to improve my craft.Thank you



Manager
Status: suffer now and live forever as a champion!!!
Joined: 01 Sep 2013
Posts: 126
Location: India
Dheeraj: Madaraboina
GPA: 3.5
WE: Information Technology (Computer Software)

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
13 Apr 2014, 05:48
Assume L =x then K= x+3 j=x+1 and M= x+2 .
Total Sum = x+x+1+x+2+x+3= 4x+6 Substitute X =12 (random guess) then we can find 54 is answer



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 12432
Location: United States (CA)

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
29 Jul 2015, 18:53
Hi All, The first part of this question requires translating sentences into formulas: J + 2 = K L + 3 = K J + 1 = M Even if you translated these formulas differently (but correctly), you still have a relationship among the 4 variables that needs to be discovered. You can TEST VALUES to figure out the relationship: If K = 10, then J = 8 L = 7 M = 9 Now we know that the 4 values are consecutive. To solve, you can either use "bruteforce" (since the answers are small) or algebra: BruteForce: 11 + 12 + 13 + 14 = 50 NOT ENOUGH BASED ON THE ANSWERS 12 + 13 + 14 + 15 = 54 WINNER Algebra: Call the youngest person X X + (X+1) + (X+2) + (X+3) = 4X + 6 If X = 11, total = 50 NOT ENOUGH BASED ON THE ANSWERS If X = 12, total = 54 WINNER Either way, you have the correct answer. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
Special Offer: Save $75 + GMAT Club Tests Free
Official GMAT Exam Packs + 70 Pt. Improvement Guarantee www.empowergmat.com/
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************



Manager
Joined: 10 Jun 2015
Posts: 118

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
17 Aug 2015, 03:40
chineseburned wrote: Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
A. 51 B. 52 C. 53 D. 54 E. 55 let the age of Lillian is L Kylie's age is L+3 Joan's age is L+1 Miriam's age is L+2 combined age is 4L+6, which is even The first part is a multiple of 4 44+6 or 48+6 or 52+6 Hope, you got it The correct option is D



Senior Manager
Joined: 07 Sep 2014
Posts: 400
Concentration: Finance, Marketing

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
23 Aug 2016, 04:27
Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
A. 51 B. 52 C. 53 D. 54 E. 55
J =k2 K= L+3 => J =L+32 M = J+1
J+K+L +M = J+J+2+J1+J+1 4J+2 so D



Director
Joined: 26 Oct 2016
Posts: 649
Location: United States
Concentration: Marketing, International Business
GPA: 4
WE: Education (Education)

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
10 Jan 2017, 06:46
Total age = x + x1 + x2 + x3 = 4x  6 After arriving at this stage can this be said that all values except 54 will yield a decimal value of x and as age cannot be in decimal the answer is 54? Please suggest.
_________________
Thanks & Regards, Anaira Mitch



Senior SC Moderator
Joined: 14 Nov 2016
Posts: 1322
Location: Malaysia

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
12 Jan 2017, 17:37
agold wrote: D
J = K  2 K = 3 + L M = 1 + J
L = 12 K = 15 27 J = 13 40 M = 14 54 agold, How do you know L=12?
_________________
"Be challenged at EVERY MOMENT."
“Strength doesn’t come from what you can do. It comes from overcoming the things you once thought you couldn’t.”
"Each stage of the journey is crucial to attaining new heights of knowledge."
Rules for posting in verbal forum  Please DO NOT post short answer in your post!
Advanced Search : https://gmatclub.com/forum/advancedsearch/



Intern
Joined: 17 Oct 2016
Posts: 4

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
04 Sep 2017, 15:34
While I used the same approach (reduced J: J+(J+2)+((J+2)3)+J+1 = 4J+2)
A shortcut to know which numbers to test would be that you know the number must be even  so only 52 or 54
Another way to look at this is that based off of the age differences, you have J and K being an even number apart. They are either both even or both odd.
K and L are an odd number apart, so L is the opposite of K. J and M are an odd number apart, so M is the opposite of J.
This means the sum of ages would be 2 odd + 2 even numbers, which will always come out as even.



Senior Manager
Status: love the club...
Joined: 24 Mar 2015
Posts: 275

Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda
[#permalink]
Show Tags
19 Oct 2017, 19:01
chineseburned wrote: Joan, Kylie, Lillian, and Miriam all celebrate their birthdays today. Joan is 2 years younger than Kylie, Kylie is 3 years older than Lillian, and Miriam is one year older than Joan. Which of the following could be the combined age of all four women today?
A. 51 B. 52 C. 53 D. 54 E. 55 the problem is solved as soon as the data, given, are elegantly simplified given j = k 2 k = L + 3 m = j + 1 So j = k2 so far so good k = L +3 L = k  3 now manageable m = j + 1 or m = k2 + 1 putting the value of j or m = k  1 now we are in business j + k + L + m = k 2 + k + k3 + k1 =4k  6 only D fits in




Re: Joan, Kylie, Lillian, and Miriam all celebrate their birthda &nbs
[#permalink]
19 Oct 2017, 19:01






