kevincan
Lena can complete a task in 3 hours and works twice as fast as Johanna. Johanna begins working on the task without Lena, and then two of them complete the task together 1 3/4 hours after Lena began working. How long did Johanna work by herself ?
A. 36 minutes
B. 40 minutes
C. 45 minutes
D. 48 minutes
E. 54 minutes
Lena can complete a task in 3 hrs.
The efficiency of Lena and Johanna is 2:1.
The the time ratio of Lena and Johanna = 1:2
If the ratio of 1 equals 3 hrs, then 2 equals 6 hours.
They both work for 1 (3/4) hours = (7/4) hours.
Let’s take the total work to be 6 units.
Work = Efficiency * time
The units of work completed by both Lena and Johanna in (7/4) hours is ?
(2+1)* (7/4) = 21/4 units of work is completed.
Johanna * t + (21/4) = 6
Johanna * t = 6-(21/4)
We know the efficiency of Johanna is 1.
Therefore, t = (3/4)
Converting into minutes = (3/4)*60 =
45 minutes. Option C