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25 Apr 2025, 00:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
77% (03:02) correct
23%
(02:40)
wrong
based on 99
sessions
History
Date
Time
Result
Not Attempted Yet
John and Jack are among 10 students who write an examination. John scored 80 marks. The average score of the 8 students other than them is 72.5. The average score of all the 10 students is one more than the average score of the 9 students other than John. The score of Jack is
A. 40
B. 45
C. 50
D. 55
E. 60
A. 40
B. 45
C. 50
D. 55
E. 60
25 Apr 2025, 01:00
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Bunuel
Total of 8 student other than John and Jack = 72.5*8 = 580
John = 80
Jack = x
Total Of all other than John = (580x)/9
AVerage of all students = (580+80+x)/10 = (660+x)/10
(660+x)/10 = 1 + (580+x)/9
i.e. 9(660 + x) = 90 + 10(580+x)
5940 + 9x = 5890 + 10x
x = 50
Answer: Option C
Related Video:
25 Apr 2025, 01:21
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other 8 = 72.5*8=580
John=80
((580+80+jack)/10)-1 = (580+Jack)/9
Solving for Jack,we get jacks score to be 50
John=80
((580+80+jack)/10)-1 = (580+Jack)/9
Solving for Jack,we get jacks score to be 50
