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24 Jan 2024, 02:25
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (01:34) correct
24%
(02:11)
wrong
based on 404
sessions
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Last Saturday a certain circus charged $6 per adult ticket and $3 per child ticket. Was the circus' revenue from adult and child tickets sold last Saturday greater than $2,500 ?
(1) The number of adult tickets sold last Saturday was greater than 1/3 of the number of child tickets sold last Saturday.
(2) The total number of adult and child tickets sold last Saturday was greater than 850.
2024-01-24_13-24-26.png [ 63.8 KiB | Viewed 5239 times ]
(1) The number of adult tickets sold last Saturday was greater than 1/3 of the number of child tickets sold last Saturday.
(2) The total number of adult and child tickets sold last Saturday was greater than 850.
Attachment:
2024-01-24_13-24-26.png [ 63.8 KiB | Viewed 5239 times ]
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26 Jan 2024, 15:21
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guddo
Let \(a\) be the # of Adult tickets and let \(c\) be the # of child tickets.
We need to find whether \(6a+3c > 2500\)
(1) The number of adult tickets sold last Saturday was greater than of the number of child tickets sold last Saturday.
Clearly insuff. but just to illustrate:
If \(a =2\) and \(c=1\), we have a NO
If \(a=1000\) and \(c=1,\) we have a YES
INSUFF.
(2) The total number of adult and child tickets sold last Saturday was greater than 850.
\(a+c>850\)
Let's suppose all were child tickets then revenue would be \(850 *3 = 2550\)
Hence even considering the lesser of the two, we are getting revenues more than \(2500.\)
Hence even if we have one adult ticket and rest child tickets or any other combination of adult and child tickets, the revenue would still be more than \(2500.\)
SUFF.
Ans B
Hope it helped.
17 Nov 2024, 06:52
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let a be number of adult tickets sold and likewise c be the no. of child tickets sold.
we're reqd to determine whether 6a+3c>2500 or not.
S1: a>1/3c
which implies 6a+3c> 6(1/3)c+3c or 6a+3c>5c
which doesnt give us any info so INSUFFICIENT
S2: a+c>850
or a>850-c
then 6a+3c> 6(850-c)+3c
or 6a+3c>5100-3c
or a>850
therefore even if we consider lowest possible value of c i.e. c=0, and lowest possible value of a i.e. a=851 then 6a+3c=
851(6)=5106, which is clearly greater than 2500.
hence B is sufficient.
we're reqd to determine whether 6a+3c>2500 or not.
S1: a>1/3c
which implies 6a+3c> 6(1/3)c+3c or 6a+3c>5c
which doesnt give us any info so INSUFFICIENT
S2: a+c>850
or a>850-c
then 6a+3c> 6(850-c)+3c
or 6a+3c>5100-3c
or a>850
therefore even if we consider lowest possible value of c i.e. c=0, and lowest possible value of a i.e. a=851 then 6a+3c=
851(6)=5106, which is clearly greater than 2500.
hence B is sufficient.
guddo
