Last year, a certain public transportation system sold an average

Question

Last year, a certain public transportation system solad an average (arithmetic mean) of 41 000 tickets per day on weekdays (Monday through Friday) and an average of 18 000 tickets per day on Saturday and Sunday. Which of the following is closest to the total number of tickets sold last year?

A/ 1 million
B/ 1.25 million
C/ 10 million
D/ 12.5 million
E/ 125 million

(A) 1 million
(B) 1.25 million
(C) 10 million
(D) 12.5 million
(E) 125 million

iruns0metimes · Accepted Answer

With the answer choices provided, I would say it is safe to approximate in this manner...

41,000 x 5 + 18,000 x 2 = 241,000 (approx to 240,000)

52 weeks in a year (approx to 50)

Now, since 50 is much like .50 we have 12,000,000

Knowing that we lessened both values in our approximation, 12.5 million is apparent.

Hope this helps!

BrentGMATPrepNow · Answer

The word "  closest  " suggests that we can use some estimation here.

Let's first estimate the number of tickets sold  PER WEEK 
 41,000 tickets per day on  weekdays   
(5)(41,000) = 205,000

18,000 tickets per day on  weekends   
(2)(18,000) = 36,000

So, total tickets sold  PER WEEK  = 205,000 + 36,000 = 241,000
To make our calculations easier, let's round it off to  240,000  tickets  per week

There are 52 weeks in the years, so the TOTAL (annual) ticket sales is (52)( 240,000 )
HOWEVER, since the GMAT is not testing whether or not you are a human calculator, we can probably just say there are  50  weeks in a year.

( 50 )( 240,000 ) = 12,000,000
Of course, there are actually 52 weeks in the year, so the correct answer is a BIT MORE than 12,000,000

Choose D

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Brindusa · Answer

I guess 10 mil is the corest answer:

(2/7)*365*18,000+(5/7)*365*41,000=10,6 mil

iruns0metimes · Answer

If you type that into the calculator, it results in 12.6 mil

, 12.5 mil, is the correct answer... see 2 posts above for quick approx method

gmat1220 · Answer

One year = 52 weeks
1K = 10^3
1M = 10^6
1 week sale = weekend sale + weekday sale = (41K * 5) + (18K * 2) = 205K + 36K = 241K
One year sale = 241K *52 = (241*52)K

241 * 52 = 12.5K (approx)

One year sale = 12.5K * K = 12.5 M

la1212 · Answer

Last year, a certain public transportation system solad an average (arithmetic mean) of 41 000 tickets per day on weekdays (Monday through Friday) and an average of 18 000 tickets per day on Saturday and Sunday. Which of the following is closest to the total number of tickets sold last year?

A/ 1 million
B/ 1.25 million
C/ 10 million
D/ 12.5 million
E/ 125 million

average = sum/# of terms

weekdays
41000 = x/5 days
205,000 = x (total tickets sold per week)

weekend
18000 = x/2 days
36000 = x (total tickets sold per week)

so...205k+36k * 52 weeks = 12.5 mil

MHIKER · Answer

41000*5+1800*2=241000*52=12532000/1000000=12.532
So, D 12.5

RSOHAL · Answer

For whole week:

41,000 * 5 + 18,000 * 2

1000 = K
Ballpark now to simplify calculations:
40K*5 + 18K*2 =200K + 36K= 236K

Number of weeks in year 52, ballpark and let's calculate with 50

236K * 50 = 11,800,K
~ 12 M. which is closest to 12.5 M answer D.

dave13 · Answer

Why are you counting 52 weeks ?

there are 4 weeks in month and 12 month in a year hence 4*12 = 48

Bunuel · Answer

How many days are there in one year? Divide that by 7. What do you get?

ScottTargetTestPrep · Answer

The total number of tickets sold in a week is:

41,000 x 5 + 18,000 x 2 = 205,000 + 36,000 = 241,000

Since there are 52 weeks in a year, then the total number of tickets sold in a year is:

241,000 x 52 ≈ 250,000 x 50 = 12,500,000

Answer: D

EMPOWERgmatRichC · Answer

Hi All,

We're told that last year, a certain public transportation system sold an average (arithmetic mean) of 41,000 tickets per day on weekdays (Monday through Friday) and an average of 18,000 tickets per day on Saturday and Sunday. We're asked which of the following is closest to the total number of tickets sold last YEAR. Since the answer choices are rather 'spread out', we can use a bit of estimation and some Arithmetic to answer this question.

To start, we can calculate the average number of tickets sold each WEEK: 
(5)(41,000) + (2)(18,000) = 205,000 + 36,000 = 241,000/week

241,000 is a little less than 250,000. Thus, since each MONTH will be a little MORE than 4 weeks (with the exception of February, which would be 4 weeks exactly), in a typical month, a bit MORE than 1 million tickets will be sold. Over the course of a full year, the 12 months would lead to total sales over 12 million. There's only one answer that matches...

Final Answer:  D

GMAT assassins aren't born, they're made, 
Rich

yannichc · Answer

my method

if it was 41,000 per day for 365 = 36*41 + 000 = roughly 15m

18,000*360 roughly 7m

narrow down to C or D

since more weekdays than weekends the answer will be more closely weighted to 15 than 7 therefore answer choice D

ArnauG · Answer

To determine the total number of tickets sold last year, we need to calculate the sum of the tickets sold on weekdays and weekends.

On weekdays, the average number of tickets sold per day is 41,000.
There are 5 weekdays in a week (Monday through Friday).
So, the total number of tickets sold on weekdays in a week is 41,000 * 5 = 205,000.

On weekends, the average number of tickets sold per day is 18,000.
There are 2 days in a weekend (Saturday and Sunday).
So, the total number of tickets sold on weekends in a week is 18,000 * 2 = 36,000.

Now, let's calculate the total number of tickets sold in a week:
Total = Tickets sold on weekdays + Tickets sold on weekends
Total = 205,000 + 36,000 = 241,000

Since there are 52 weeks in a year, we can calculate the approximate total number of tickets sold last year:
Approximate Total = Total tickets sold per week * Number of weeks = 241,000 * 52 = 12,532,000

Among the given options, the closest number to 12,532,000 is (D) 12.5 million.

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Last year, a certain public transportation system sold an average

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Last year, a certain public transportation system sold an average

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