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# Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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Sally grew 200% more than Jon.

Interpretation: Sall grew 1 inch same as Jon and also grew 200% more.

So, Sally grew total of 300%. I.e. 3 inch.

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Answer D : The term more than refers to difference in growth. Hence 1+2=3

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Bunuel
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4

$$\frac{(200+100)}{100}*1 = 3$$

Hence, correct answer must be (D)
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
If nothing else the question states that Sally grew 200% more than Joe did, and that Joe grew an inch. Right off the bat that eliminates A and B.
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Sally is increased by 200% = ( 1 + 2 ) = 3
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Ans : D
1+(200*1/100) = 1+2 =3

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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Bunuel
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4

Easy question, but the wording is tricky

$$\frac{Change in growth}{Joe's Growth}$$ = Percent

$$\frac{Sally's Growth - Joe's Growth}{Joe's Growth}$$ = 200% (which is 2)

$$\frac{X - 1}{1}$$ = 2

$$x-1 = 2$$

$$X = 3$$

Sally grew 3 inches, so Answer is D
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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Bunuel
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4

Joe=1
Sally=1+200%of1=3

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Bunuel
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4

Have you trained your brain to associate percent with divide by 100 yet? If not let's ground that concept here:

Percent more can be represented as (1+percent more). So (1 + 200/100) = 1+2 = 3. So then we can say that Joe = 1, and Sally grew 1 inch TIMES 3 (i.e. 200% more). So Sally grew 3 inches, D is the answer.
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Bunuel
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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Video solution from Quant Reasoning:
Subscribe for more: https://www.youtube.com/QuantReasoning? ... irmation=1
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
Top Contributor
The word "more" includes "addition" as an implied meaning.

So, 200% more = 1 + 200% of 1

= 1 + 2 = 3 inches.

(option d)

D.S
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre [#permalink]
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