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Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre

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Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 15 Jun 2016, 01:27
3
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A
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D
E

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Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4
Spoiler: OA

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 15 Jun 2016, 03:13
1
1+200% of 1 = 1 + 2 = 3 inches
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 15 Jun 2016, 23:29
Sally grew 200% more than Jon.

Interpretation: Sall grew 1 inch same as Jon and also grew 200% more.

So, Sally grew total of 300%. I.e. 3 inch.

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 05 Dec 2016, 18:27
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Bunuel wrote:
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4


We are given that last year Joe grew 1 inch and that Sally grew 200 percent more than Joe grew. This means Sally grew 300 percent as much as Joe grew. That is, Sally grew 3 times as much as Joe.

Thus, Sally grew 3 x 1 = 3 inches.

Answer: D
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 05 Dec 2016, 22:32
Answer D : The term more than refers to difference in growth. Hence 1+2=3

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 06 Dec 2016, 08:18
Bunuel wrote:
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4


\(\frac{(200+100)}{100}*1 = 3\)

Hence, correct answer must be (D)
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 08 Dec 2016, 14:44
If nothing else the question states that Sally grew 200% more than Joe did, and that Joe grew an inch. Right off the bat that eliminates A and B.
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 21 Dec 2016, 14:56
Sally is increased by 200% = ( 1 + 2 ) = 3
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 27 Apr 2018, 12:38
Ans : D
1+(200*1/100) = 1+2 =3

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 27 Jan 2019, 13:19
Bunuel wrote:
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4


Easy question, but the wording is tricky

\(\frac{Change in growth}{Joe's Growth}\) = Percent

\(\frac{Sally's Growth - Joe's Growth}{Joe's Growth}\) = 200% (which is 2)

\(\frac{X - 1}{1}\) = 2

\(x-1 = 2\)

\(X = 3\)

Sally grew 3 inches, so Answer is D
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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre  [#permalink]

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New post 17 May 2019, 22:46
Bunuel wrote:
Last year Joe grew 1 inch and Sally grew 200 percent more than Joe grew. How many inches did Sally grow last year?

A) 0
B) 1
C) 2
D) 3
E) 4


Joe=1
Sally=1+200%of1=3

Answer is D

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Re: Last year Joe grew 1 inch and Sally grew 200 percent more than Joe gre   [#permalink] 17 May 2019, 22:46
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