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C
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Difficulty:
95%
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Question Stats:
35% (01:56) correct
65%
(01:48)
wrong
based on 89
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LCM of two natural numbers x and y is 161, and x and y are greater than 1. What is the value of (4x-3y)?
1. y>x
2. x and y are co-prime.
1. y>x
2. x and y are co-prime.
24 Jun 2019, 21:41
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Let the numbers be a and b . Then , ab= 161.
Now, co-primes with product 161 are (1, 161) and (7, 23).
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i.) Since y >x , we have y=23 and x=7.
Therefore, 4x-3y = (4 x 7)-(3 x 23) = -41
i.) SUFFICIENT
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ii.) 1 and 161 are co-prime; 7 and 23 are also co prime
ii.) INSUFFICIENT
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Now, co-primes with product 161 are (1, 161) and (7, 23).
-------------------------------------------------------------------------
i.) Since y >x , we have y=23 and x=7.
Therefore, 4x-3y = (4 x 7)-(3 x 23) = -41
i.) SUFFICIENT
--------------------------------------------------------------------------
ii.) 1 and 161 are co-prime; 7 and 23 are also co prime
ii.) INSUFFICIENT
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Rakesh1987
Current Student
Joined: 17 Jul 2018
Last visit: 31 Dec 2024
Posts: 66
Given Kudos: 100
Location: India
Concentration: Finance, Leadership
Schools: Stern '23 (M$)
GMAT 1: 760 Q50 V44
GPA: 4
Updated on: 24 Jun 2019, 23:48
Originally posted by Rakesh1987 on 24 Jun 2019, 23:25.
Last edited by Rakesh1987 on 24 Jun 2019, 23:48, edited 1 time in total.
Last edited by Rakesh1987 on 24 Jun 2019, 23:48, edited 1 time in total.
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nick1816
LCM of two numbers x and y is 161, and x is greater than 1. What is the value of (4x-3y)?
1. y>x
2. x and y are co-prime.
1. y>x
2. x and y are co-prime.
161=7*23.
Numbers can be 7,23; 1,161; 7,161; 23,161.
1. Y>x. Too many possibilities. Insufficient
2. x and Y are co-prime. two possibilities: 7,23 and 1,161. Insufficient.
Combined we get, from 2) that they are integers without common factor.
and from 1) we rule out 1*161. and as Y>x, only scenario remains is y=23 and x=7. 4x-3y=4*7-3*23=-41. Sufficient.
Answer is C.
