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Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 01:52
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88% (02:28) correct 12% (03:11) wrong based on 136 sessions
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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 09:12
Bunuel wrote: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot dog eating contest. If Jim ate four times as many hot dogs as Leon but half as many hot dogs as Billy, how many more hot dogs did Billy eat than Leon?
A. 13 B. 20 C. 39 D. 42 E. 60
Kudos for correct solution. hi, two ways you can tackle these problems, although the concept/logic is same 1) ratio clearly ratio between B:J:L=8:4:1.. since J:L=4:1 and B:J=2:1.. let the common ratio be x, so total=13x and x=78/13=6.. difference in B and L= (81)x=7*6=42.. D
2) Equations.. L+B+J=78.. Jim ate four times as many hot dogs as Leon J=4L.. Jim ate half as many hot dogs as Billy J=B/2 or B=2J.. since L+B+J=78.. L+4L+2*4L=78.. L=78/13=6.. so B=2*4L=8*6=48..
ans 486=42..
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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 09:25
Since Leon has eaten the lowest number of htdgs, Let's consider, the number of htdgs eaten by Leon= x and htdgs etn by Jimmy=4x And by Billy=2*4x=8x
Total number of htdgs= x+4x+8x = 13x
13x=78 => x=6
we need to find difference between Billy's and Leon's consumption, i.e. 8xx = 7x
7*6=42
D is the answer.



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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 09:28
Bunuel wrote: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot dog eating contest. If Jim ate four times as many hot dogs as Leon but half as many hot dogs as Billy, how many more hot dogs did Billy eat than Leon?
A. 13 B. 20 C. 39 D. 42 E. 60
Kudos for correct solution. Let \(l\), \(b\) and \(j\) represent the number of hotdogs eaten by Leon, Billy and Jim, respectively. Jim ate four times as many hot dogs as Leon. so, \(j = 4l\) But Jim ate half as many hot dogs as Billy so, \(j = 1/2b\) replace \(j = 4l\) in the above equation. we get: \(4l = 1/2b\) or \(b = 8l\) We know, \(j + l + b = 78\) replace, \(j = 4l\) and \(b = 8l\) in the above equation, we get \(4l + l + 8l = 78\) This means, \(13l = 78\) or \(l = 6\) Leon ate 6 hotdogs. \(b = 8l\) = 8 x 6 = 48 Billy ate 48 hotdogs How many more hot dogs did Billy eat than Leon? = \(b  l\) = 48  6 = 42 Hence, D is the correct answer.



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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 11:52
L+b+j=78 J=4l > l=j/4 J=b/2 > b=2j
J/4+2j+j=78 13j= 78×4 J=24 B=48 L=6
Bl=42 Ans:D



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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 15:51
Bunuel wrote: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot dog eating contest. If Jim ate four times as many hot dogs as Leon but half as many hot dogs as Billy, how many more hot dogs did Billy eat than Leon?
A. 13 B. 20 C. 39 D. 42 E. 60
Let x = # of hot dogs that Jim ate Jim ate four times as many hot dogs as LeonIn other words, Leon ate 1/4 as many hot dogs as Jim ate So, x/4 = # of hot dogs that Leon ate Jim ate half as many hot dogs as BillyIn other words, Billy ate twice as many hot dogs as Jim ate So, 2x = # of hot dogs that Billy ate In TOTAL they ate 78 hot dogs So, x + x/4 + 2x = 78 Solve to get: x = 24 So... Jim ate 24 hot dogs Leon ate 6 hot dogs Billy ate 48 hot dogs How many more hot dogs did Billy eat than Leon?48  6 = 42 = D Cheers, Brent
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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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23 Feb 2016, 15:52
Related ResourcesThe following free videos cover the concepts/strategies that are useful for answering this question: Cheers, Brent
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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot
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27 Feb 2018, 09:42
Bunuel wrote: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot dog eating contest. If Jim ate four times as many hot dogs as Leon but half as many hot dogs as Billy, how many more hot dogs did Billy eat than Leon?
A. 13 B. 20 C. 39 D. 42 E. 60 We can let the number of hot dogs eaten by Leon, Billy, and Jim = L, B, and J, respectively, and create the equations: L + B + J = 78 and J = 4L J/4 = L and J = (1/2)B 2J = B Substituting, we have: J/4 + 2J + J = 78 J/4 + 3J = 78 Multiplying by 4 we have: J + 12J = 312 13J = 312 J = 24 Thus, B = 2(24) = 48 and L = 24/4 = 6. So Bill ate 48  6 = 42 more hot dogs than Leon. Answer: D
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Re: Leon, Billy, and Jim ate an astounding total of 78 hot dogs in a hot &nbs
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