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M03 #24 DS Question [#permalink]
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09 Dec 2008, 16:09
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This topic is locked. If you want to discuss this question please repost it in the respective forum. Is \(N^x\) even? 1. \(N\) is even 2. \(x^23x+2 = 0\) Source: GMAT Club Tests  hardest GMAT questions REVISED VERSION OF THIS QUESTION IS HERE: m0324dsquestion73770.html#p1249364



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Re: M03 DS Question [#permalink]
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09 Dec 2008, 16:13
I think the answer is A.
But the OA is C.
An even number raised to any power is always even.
(2) provides the power as 1 or 2. But doesn't give anything about the base.



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Re: M03 DS Question [#permalink]
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09 Dec 2008, 17:15
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Quote: An even number raised to any power is always even. The power needs to be a positive integer for this statement to be true. You need the second equation to find that x is a positive integer.



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Re: M03 DS Question [#permalink]
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09 Dec 2008, 23:04
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topmbaseeker wrote: Is \(N^x\) even?
1. \(N\) is even 2. \(x^23x+2 = 0\)
(C) 2008 GMAT Club  m03#24
* Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient * Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient * BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient * EACH statement ALONE is sufficient * Statements (1) and (2) TOGETHER are NOT sufficient has to be C. 1: n = lets say 2 but x could be 1, 0, 0.5, 2. Then in all cases, n^x is not an even. so nsff.. 2: x = 1 or 2 but what is n? nsf. therefore, C.
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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 05:24
Good question. Even i picked A on the first go. However, after seeing the answer, C made sense



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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 10:34
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Hi, C is the correct option because even if N is even N^x can be odd. Consider for example N = 4 N^0 = 4^0 =1 which is odd If we consider the second statement then we come to know that x can be either 1 or 2. So from 1 and 2 both we can answer the question properly hence the solution for this is C.



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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 12:33
i made the same mistake...i chose A....well that was tricky one...



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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 15:35
Easy one..!!
C. Both Stmt together solve the purpose.
Since to be even depends upon both N & x .we need to have both to conclude.



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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 18:59
How did you get x=1 or X=2 from x2 3X+2 = 0. Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ?



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Re: M03 #24 DS Question [#permalink]
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15 Jul 2010, 19:13
x23x+2=0
x2x2x+2=0
x(x1) 2(x1)=0 (x2)(x1)=0
=>x=1 or x=2



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Re: M03 #24 DS Question [#permalink]
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16 Jul 2010, 06:48
Francois wrote: How did you get x=1 or X=2 from x2 3X+2 = 0. Just from trying figures starting from 0 or can the equation be written in a way that makes it solution obvious ? Hi, You need to know the basics of quadratic equation to solve. Try searching for Crammers Rule.



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Re: M03 #24 DS Question [#permalink]
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19 Jul 2011, 05:46
I chose (A) at first as well. We don't know whether X is an integer or not, that made sense for me. So the correct answer is (C) as far as we learn that N is a positive integer.



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Re: M03 #24 DS Question [#permalink]
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23 Jul 2012, 14:15
Nice trick question . Easy but missed it. Accounted for the negative numbers as well but missed the fact that for a simple (2^1) it fails. Good one.
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Re: M03 #24 DS Question [#permalink]
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23 Jul 2013, 05:58
The answer is the first option. An even number raised to any number is always even. However, for the quadratic equation, x=1,2. And it cannot be certainly be told if N^x is even without knowing the value of N.



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Re: M03 #24 DS Question [#permalink]
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23 Jul 2013, 06:26
Statement 1: Insufficient. x could be 1 or x could be 0. Statement 2: Insufficient. After factoring x = 2 or x = 1. We also do not know anything about N.
Combined 1 + 2. We know that N is even. An even number raised to either 1 or 2 would still be EVEN. Sufficient. C.



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Re: M03 #24 DS Question [#permalink]
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23 Jul 2013, 06:51



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Re: M03 #24 DS Question [#permalink]
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08 Jul 2014, 05:29
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This question reminds us the importance of fraction, negatives and zero. I lost out on my previous GMAT cuz of this, so now before freezing on the answer for variables in question always remember frazen(fractions, zero and negatives) Posted from my mobile device
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Re: M03 #24 DS Question [#permalink]
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08 Jul 2014, 07:48
Never forget about negatives!



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M03 #24 DS Question [#permalink]
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08 Jul 2014, 08:17
Bunuel wrote: BELOW IS REVISED VERSION OF THIS QUESTION:
If \(n\) is a positive integer, is \(n^x\) an even number?
(1) \(n\) is an even number (2) \(x^23x+2 = 0\)
If n is not a positive integer. I think the answer is E. Cuz n could be 0, and 0^p always equals to 1.



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Re: M03 #24 DS Question [#permalink]
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08 Jul 2014, 10:28
N^x will must be even if a) N is even & b) x is non negative & non zero
i) Says N is even but doesn't say abt x ii) Gives x as 1 or , but doesn't say abt N combining both we get N even & x 1 or 2 so N^x must be even.. Hence 'C'




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