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09 Jun 2012, 03:25
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Quantitative :: Data sufficiency :: M06-04
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If g is an integer what is the value of (−1)^(g^4−1)?
(1) g^2<1
(2) g^2+2g−3<0
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH stamenents TOGETHER are sufficient, but NEITHER stamenent ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
Mark as a guess Hide Answer
(1) g^2<1 → since g is an integer then g=0. Sufficient to calculate the value of (−1)g4−1.
(2) g^2+2g=0 → g(g+2)=0 → g=0 or g=−2. Since both possible values of g are even then (−1)even4−1=(−1)even−1=(−1)odd=−1. Sufficient.
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I answered A. This question has a problem. (2) g^2+2g−3<0 ---->> g= -1 or g=3, how come the solution changes the equation totally??
Flag for Review
If g is an integer what is the value of (−1)^(g^4−1)?
(1) g^2<1
(2) g^2+2g−3<0
Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
BOTH stamenents TOGETHER are sufficient, but NEITHER stamenent ALONE is sufficient.
EACH statement ALONE is sufficient.
Statements (1) and (2) TOGETHER are NOT sufficient.
Mark as a guess Hide Answer
(1) g^2<1 → since g is an integer then g=0. Sufficient to calculate the value of (−1)g4−1.
(2) g^2+2g=0 → g(g+2)=0 → g=0 or g=−2. Since both possible values of g are even then (−1)even4−1=(−1)even−1=(−1)odd=−1. Sufficient.
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I answered A. This question has a problem. (2) g^2+2g−3<0 ---->> g= -1 or g=3, how come the solution changes the equation totally??
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Bull78
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07 Jul 2012, 08:37
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Guys please correct me if I am wrong
g^4-1 = g^4/g = g^3 therefore we are concerned about the value of g^3, as if it yields an even number the answer will become 1
1.- g^2 < 1 There is no other number rised to the power of two that yields a negative result, so g = 0, sufficient
2.- x= -1 or x = 3, as each of the results is odd, it is sufficient to realize that the value of g is -1.
So answer is still D
g^4-1 = g^4/g = g^3 therefore we are concerned about the value of g^3, as if it yields an even number the answer will become 1
1.- g^2 < 1 There is no other number rised to the power of two that yields a negative result, so g = 0, sufficient
2.- x= -1 or x = 3, as each of the results is odd, it is sufficient to realize that the value of g is -1.
So answer is still D
