VeritasPrepKarishma BunuelA-----------------X-----------------------------------------------------------------B
Can you please share your thoughts on this problem.
I have tried to visualize it this way. Say we have 100m distance between the two points. Now, See Buster has started 20 minutes before but still reaches at the same time that means his time is t + 20 if t is the time taken by charlie to reach 100 meters distance.
Now, one thing we know is that : charlie has higher speed than buster. So far so good. But how do we know what happens before they cross, at the time of crossing and after they have crossed is something I need more clarification on.
When Charlie starts Buster has already covered a distance equal to 20 times his speed in miles per hour. When charlie and Buster meet at say X point then we have D-X more than X Since if both we running at equal speed then starting 20 minutes early they would have met beyond the midpoint of the D.
I think, I am getting lost beyond this point.
Can you help me get organized from here?
B takes \(x\) min and C takes \(x-20\)....
B is at half the distance at \(\frac{x}{2}\).....
so lets see where is C at this time -20 min, as he starts 20 minutes later = \(\frac{x}{2} -20\)..
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