Bunuel
Buster leaves the trailer at noon and walks towards the studio at a constant rate of B miles per hour. 20 minutes later, Charlie leaves the same studio and walks towards the same trailer at a constant rate of C miles per hour along the same route as Buster. Will Buster be closer to the trailer than to the studio when he passes Charlie?
(1) Charlie gets to the trailer in 55 minutes.
(2) Buster gets to the studio at the same time as Charlie gets to the trailer.
(1) is insufficient because we dont have any info for Buster from this
(2)
Let trailer and studio be "D" distance away.
Buster and Charlie will meet after (D-B/3)/(B+C) time.
Buster's distance from trailer when he meets Charlie = B/3 + B*((D-B/3)/(B+C)) = B/3(1-B/(B+C)) + BD/(B+C) = BC/3(B+C) + BD/(B+C)
Buster gets to studio after ( D-B/3 )/B
Charlie gets to studio after D/C
According to (2) both of them are equal
(D-B/3)/B = D/C <=> D = BC/3( C-B )
substitute the value of D, we get Buster's distance from trailer when he meets Charlie = (B/(B+C))( C/3 + BC/(3(C-B)) ) = (BC/(3(B+C)))( C/(C-B) )
= D*(C/(B+C)) > D/2 as we know that C>B as Charlier covers D in the same time as Buster covers D-B/3.
C>B <=> 2C > B+C <=> C/(B+C) > 1/2