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M06-22

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M06-22  [#permalink]

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New post 15 Sep 2014, 23:28
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A
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Difficulty:

  25% (medium)

Question Stats:

73% (00:43) correct 27% (00:41) wrong based on 139 sessions

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If 53 students are enrolled in both the CS103 (Algorithms and Data Structures) and the M101 (Mathematics for Computer Science) classes, how many of the CS103 students are not enrolled in M101?


(1) 72 students are taking M101.

(2) 59 students are taking CS103.

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Re M06-22  [#permalink]

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New post 15 Sep 2014, 23:28
Official Solution:


Statement (1) by itself is insufficient. We don't know anything about the number of students taking CS103.

Statement (2) by itself is sufficient. S2 tells us that 59 students take CS103. We know that 53 of these 59 students take M101 as well. Thus, we find that \(59 - 53 = 6\) students are not enrolled in M101.


Answer: B
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Re: M06-22  [#permalink]

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New post 17 Aug 2015, 20:41
Hello Bunuel,
The question stem is silent about the number of students who did not enroll in any of the course.
From the solution, it can be seen that that value is taken ZERO.

How can we assume this as such ?
Is it a convention that in a set theory question , if the stem is silent about this fact we assume it to be zero ?

Thanks.
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Re: M06-22  [#permalink]

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New post 18 Aug 2015, 00:39
fetchnitin wrote:
Hello Bunuel,
The question stem is silent about the number of students who did not enroll in any of the course.
From the solution, it can be seen that that value is taken ZERO.

How can we assume this as such ?
Is it a convention that in a set theory question , if the stem is silent about this fact we assume it to be zero ?

Thanks.


The question asks "how many of the CS103 students are not enrolled in M101", so we are not interested in students who are not enrolled in any of the classes. It may or may not be 0 but we don't care.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: M06-22  [#permalink]

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New post 03 Aug 2016, 02:36
I used a venn diagram with two overlapping circle to approach this question, one circle each for the two classes.
The intersection of the two circles is 53 as 53 students take both classes.

Statement 1 does not tell us anything about the circle for CS students so nut sufficient.
Statement 2 tells us the total circle for CS is 59 as we know 53 already overlaps the remainder must be CS only which gives us 59 - 53 = 6. Sufficient.
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Re M06-22  [#permalink]

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New post 21 May 2017, 21:15
I think this is a high-quality question. Are we not going to take neither into account?
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Re: M06-22  [#permalink]

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New post 03 Aug 2018, 07:54
Dont like it ambiguous
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Re: M06-22 &nbs [#permalink] 03 Aug 2018, 07:54
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