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M09-10

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M09-10 [#permalink]

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A wholesaler sells computers on following conditions: the first 100 computers cost $500 each and each computer above 100th costs $400. If the wholesaler received $57,600 as a result of the deal, how many computers did he sell?

A. 109
B. 117
C. 119
D. 121
E. 123
[Reveal] Spoiler: OA

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Re M09-10 [#permalink]

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New post 15 Sep 2014, 23:39
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Official Solution:

A wholesaler sells computers on following conditions: the first 100 computers cost $500 each and each computer above 100th costs $400. If the wholesaler received $57,600 as a result of the deal, how many computers did he sell?

A. 109
B. 117
C. 119
D. 121
E. 123


Say the wholesaler sold \(n\) computers. Then:

\(100*500+(n-100)*400=57,600\);

\((n-100)*400=7,600\);

\(n-100=19\);

\(n=119\).


Answer: C
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: M09-10 [#permalink]

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New post 03 Sep 2017, 15:06
100*500 = 50,000 -> leaves 7,600

7,600/400=x (note here that 20x400=8,000, so -400 = 7,600)

x=19

100+19 = Answer C
Re: M09-10   [#permalink] 03 Sep 2017, 15:06
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