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M10-19

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M10-19  [#permalink]

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New post 16 Sep 2014, 00:42
1
12
00:00
A
B
C
D
E

Difficulty:

  75% (hard)

Question Stats:

40% (00:45) correct 60% (00:34) wrong based on 131 sessions

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Re M10-19  [#permalink]

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New post 16 Sep 2014, 00:42
1
Official Solution:

Statements (1) and (2) combined are insufficient. Consider \(X = Y = Z = 2\) (the answer is "yes") and \(X = Y = Z = \sqrt{2}\) (the answer is "no"). Do not assume that the numbers are all integers; the stem doesn't stipulate that.

Answer: E
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Re: M10-19  [#permalink]

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New post 21 Oct 2014, 07:14
Bunuel wrote:
Official Solution:

Statements (1) and (2) combined are insufficient. Consider \(X = Y = Z = 2\) (the answer is "yes") and \(X = Y = Z = \sqrt{2}\) (the answer is "no"). Do not assume that the numbers are all integers; the stem doesn't stipulate that.

Answer: E


While attempting this question, i tried all possible scenarios (keeping in mind that numbers may not be integers) and ultimately it boiled down to Either C or E.

Somehow could not think of \(\sqrt{2}\) as a possible option.
I was wondering if we take out the square root scenario, is there any other possible way one could still prove that using Both statements together are insufficient?
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Re: M10-19  [#permalink]

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New post 30 Jun 2015, 23:10
Really, it is a good and helpful question, I assumed that all numbers are integer.
Great! I got it.
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Re: M10-19  [#permalink]

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New post 12 May 2016, 06:00
Bunuel Vyshak
when x y z = under-root 2
we are given that x*y & y*z = even
which is under-root 2 * under-root 2 * under-root 2 * under-root 2 = 4
so xyz has to be even
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M10-19  [#permalink]

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New post 12 May 2016, 06:21
earnit wrote:
While attempting this question, i tried all possible scenarios (keeping in mind that numbers may not be integers) and ultimately it boiled down to Either C or E.

Somehow could not think of \(\sqrt{2}\) as a possible option.
I was wondering if we take out the square root scenario, is there any other possible way one could still prove that using Both statements together are insufficient?


earnit
If both X and Z are .5 and Y is 4, you will satisfy both statements and still be able to get a "No". That's what I used for solving this problem :).
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Re: M10-19  [#permalink]

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New post 12 May 2016, 19:35
Did you not think of 1/3, 6 , 1/3 either?
earnit wrote:
Bunuel wrote:
Official Solution:

Statements (1) and (2) combined are insufficient. Consider \(X = Y = Z = 2\) (the answer is "yes") and \(X = Y = Z = \sqrt{2}\) (the answer is "no"). Do not assume that the numbers are all integers; the stem doesn't stipulate that.

Answer: E


While attempting this question, i tried all possible scenarios (keeping in mind that numbers may not be integers) and ultimately it boiled down to Either C or E.

Somehow could not think of \(\sqrt{2}\) as a possible option.
I was wondering if we take out the square root scenario, is there any other possible way one could still prove that using Both statements together are insufficient?
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Re: M10-19  [#permalink]

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New post 17 May 2016, 13:36
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Just use X=1/2 Y=8 and Z=1/4

I played around with fractions and not square roots. Still got the E for answer
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Re M10-19  [#permalink]

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New post 17 Aug 2016, 04:28
I think this is a high-quality question and I agree with explanation.
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Re M10-19  [#permalink]

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New post 13 Sep 2016, 17:06
I think this is a high-quality question and I agree with explanation.
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Re: M10-19  [#permalink]

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New post 16 Sep 2016, 03:34
My approach was to find a NO answer to this question because it is easy to find a YES answer. X * Y * Z = 1/26 * 52 * 1/4 => NO
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Re: M10-19  [#permalink]

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New post 21 Nov 2016, 07:58
1
Great Question
Here we need to check if xyz is even or not
Note=> x,y,z are not mentioned to be integers.
Lets go to the statements
Statement 1
xy=even
xy=2
z=2=> xyz=even
z=1/2=> xyz=odd
hence insufficient

Statement 2
yz=even
yz=2
x=2=> xyz=even
x=1/2=> xyz=odd
hence insufficient

Now lets combine the statements
using the test cases
(x,y,z)=>2,2,2=> xyz=even
(x,y,z)=> 1/4,8,1/4=> xyz=8/16=1/2 => neither even nor odd
Hence Insufficient
Hence E
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Re: M10-19  [#permalink]

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New post 20 Mar 2018, 19:47
stonecold - Hell yeah. Good solution.

I assumed individual X , Y and Z as integer. Careless mistake, but cost me dearly :(
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Re: M10-19 &nbs [#permalink] 20 Mar 2018, 19:47
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