Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
78% (01:15) correct 22% (01:36) wrong based on 127 sessions
HideShow timer Statistics
The radius of the front wheels of a cart is half that of the rear wheels. If the circumference of the front wheels is 1 meter and the cart traveled 1 kilometer, how many revolutions did the rear wheels make?
A. \(\frac{250}{\pi}\) B. \(\frac{500}{\pi}\) C. 250 D. 500 E. 750
The radius of the front wheels of a cart is half that of the rear wheels. If the circumference of the front wheels is 1 meter and the cart traveled 1 kilometer, how many revolutions did the rear wheels make?
A. \(\frac{250}{\pi}\) B. \(\frac{500}{\pi}\) C. 250 D. 500 E. 750
The circumference of the rear wheels is twice that of the front wheels, i.e. 2 meters. Thus, the rear wheels made \(\frac{1000}{2} = 500\) revolutions.
The radius of the front wheels of a cart is half that of the rear wheels. If the circumference of the front wheels is 1 meter and the cart traveled 1 kilometer, how many revolutions did the rear wheels make?
A. \(\frac{250}{\pi}\) B. \(\frac{500}{\pi}\) C. 250 D. 500 E. 750
The circumference of the rear wheels is twice that of the front wheels, i.e. 2 meters. Thus, the rear wheels made \(\frac{1000}{2} = 500\) revolutions.
Answer: D
I thought we have to divided the distance i.e. 1000 meters with circumference i.e. 4\({\pi}\) and hence the answer should be \(\frac{250}{{\pi}}\) but I guess in the solution you have divided the the distance with radius. Is it so?
The radius of the front wheels of a cart is half that of the rear wheels. If the circumference of the front wheels is 1 meter and the cart traveled 1 kilometer, how many revolutions did the rear wheels make?
A. \(\frac{250}{\pi}\) B. \(\frac{500}{\pi}\) C. 250 D. 500 E. 750
The circumference of the rear wheels is twice that of the front wheels, i.e. 2 meters. Thus, the rear wheels made \(\frac{1000}{2} = 500\) revolutions.
Answer: D
I thought we have to divided the distance i.e. 1000 meters with circumference i.e. 4\({\pi}\) and hence the answer should be \(\frac{250}{{\pi}}\) but I guess in the solution you have divided the the distance with radius. Is it so?
No. We are given that the circumference of the front wheels is 1 meter and the radius of the front wheels is half that of the rear wheels.
Thus, the circumference of the front wheels is \(2\pi{r}=1\) and the circumference of the rear wheels is \(2\pi{(2r)}=2*2\pi{r}=2\).
So, we are dividing the distance with the circumference.
I guess it needs less math thinking than rational thinking. Hope I will explain well enough. Let's put the information we have together:
Radius of front wheel: r Radius of rear wheel: 2r
This means that when the front wheel makes 1 whole revolution, the rear one makes 2. That because its diameter (2 radii) is twice as large, so it covers twice the distance of the front wheel at the same time (if the weels were not attached, when the front wheel covers 5 meters, the back would cover 10). Put differently, since the wheels are actually attached to the same vehicle, the distance the rear wheel has covered in the same amount of time with the front is half the distance of the front (if the front wheel covered 10 meters, the read wheel covered 5).
Now, we know that the circumference is 1 meter (so, in 1 meter the cart makes 1 revolution) and that the cart covered 1 km.
In others words: 1 revolution in 1 meter x revolutions in 1000 meters? x = 1000 for the front wheel, so x = 500 for the rear wheel.
We need to find the circumference of the back tire using a relation to the circumference of the front tire.
Radius of front wheel (Rf): 1 meter = 2*Pi*Rf ---> Rf = 1/(2*Pi) meters Radius of back wheel (Rb): 2*Rf = 1/Pi meters since it is stated that the radius of the back tire is twice that of the front Circumference of back wheel (Cb) = 2*Pi*Rb = 2 meters
Very cool - its like being tricked with word changes. The question talks about radius first and then mentions (*casually*) the circumferences. I was busy trying to calculate the 2 pi R; whereas its already there! :D
I don't agree with the explanation. Question says radius is half- not circumference
Really? Let me ask you: if the radius of a circle is half that of other circle, isn't the circumference also half that of other circle?
_________________
are basically tryimg to find how many circumferences in the distance the cart travelled? So is resolution a full 360 degree circum?
thanks
One 360-degree revolution = the distance of one circumference.
I'm confused as to how the pie gets cancelled out. That confusion seems to be baked into the answer choices, hence me picking " 500/pie" rather than 500
close
78% (01:15) correct 
