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Bunuel
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Bunuel
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rokr44
Why can't I use the second statement to calculate the length of the other side using sin 45. I know the height is 10. Shouldn't the answer be B?

How do you know that height is 10 for (2)?
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Good explanation. Thank you.

Posted from my mobile device
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I think could be b) for the following reason:

We know from the stem that the area is 100, and from stmt 2 that one of the angles of the parallelogram is 45 degrees.

We know that opposite angles are equal : so we have 2 degree angles, so the other angles have to be 135 degrees

Is there not only 1 such parallelogram that has an area of 100 degrees?

Thus the lengths sides could be induced, and thus the perimeter calculated?
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TheMBmonster
I think could be b) for the following reason:

We know from the stem that the area is 100, and from stmt 2 that one of the angles of the parallelogram is 45 degrees.

We know that opposite angles are equal : so we have 2 degree angles, so the other angles have to be 135 degrees

Is there not only 1 such parallelogram that has an area of 100 degrees?

Thus the lengths sides could be induced, and thus the perimeter calculated?

I addressed that doubt here: https://gmatclub.com/forum/if-the-area- ... ml#p737846
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Hi Bunuel . Could you answer what I've missed in my reasoning?

If one side of a parallelogram has 45 degrees, we actually have 2 sides of 45 degrees and 2 sides of 135 degrees. Going further, we can make 4 45-45-90 triangles sharing the same height as one side of the triangles, thus each triangle area = 25. Once you know that each triangle has an area = 25 and 2 sides of each are equal, we could find the sides and the hypotenuse, thus the perimeter would be 2*(2*side + hypotenuse), making B the correct answer. What is wrong with that?
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See, the problem lies here. You can make 2 45-45-90 triangles but not 4 because when you drop two perpendiculars(which are heights actually), you do not know if they are making equal intercepts as the heights. Or in other words, by dropping two perpendiculars(which are heights), the internal figure thus obtained would be rectangle not square, therefore 45-45-90 degs triangle is not possible. Everything, apart from that was right.
I hope you got my point.
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Area of parallelogram =absin@ =100
from 1 we get a=10 , therefore b=10√2
hence both statement together are sufficient
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understood why option A is insufficient

- we know that area of ||gm = b x h = 100
- from St1, we know that b = 10 so we know that h is also 10.

Plugging in the values of perimeter = 2(b+l), we can NOT get the value of perimeter. Hence, St1 is insufficient.
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Bunuel
If the area of a parallelogram is 100, what is the perimeter of the parallelogram?


(1) The base of the parallelogram is 10.

(2) One of the angles of the parallelogram is 45 degrees.

The area of parallelogram = base * height

(1) If the base (a side of the parallelogram) 10 then the height is 10 too.

(2) Is insufficient.

considering both:
The 45-degree angle creates a 45-45-90 right triangle, where aside (hypotenuse). of the parallelogram is \(10\sqrt{2}\).
Now we have all the sides of the parallelogram to determine its perimeter. Sufficient.

The answer is C
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okay so AX= BX = 10. but why is AX=AD?
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ishitaagarwal59
okay so AX= BX = 10. but why is AX=AD?
because AD=10 (this is statement 1)
So, AX=AD=10,
and therefore X and D coincides
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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