Official Solution: If the area of a parallelogram is 100 square units, what is its perimeter? Refer to the diagram below:
Given: \(Area = base*height = 100\). We want to find the perimeter, \(P = 2b + 2l\), where \(b\) is the base and \(l\) is the leg (side length).
(1) The parallelogram has a base measuring 10 units.
So, \(base = height = 10\). Infinitely many cases are possible. Observe the diagram (let the distance between two horizontal and vertical points be 10 units): all 4 parallelograms have \(base = height = 10\) but they have different perimeters. Therefore, this information is not sufficient.
(2) One of the angles of the parallelogram is 45 degrees.
Clearly insufficient by itself. However, from this statement, we know that height \(BX\) and \(AX\) form an isosceles right triangle: \(height = BX = AX\).
(1) + (2) Combining both statements, from (2) we have that \(height = BX = AX\), and from (1) we have that \(base = height = 10\), so \(AX = base = AD = 10\). This means that points \(X\) and \(D\) coincide (case #4 in the diagram). Thus, leg \(AB\) becomes the hypotenuse of the isosceles right triangle with sides equal to 10 units, hence \(AB = 10\sqrt{2}\). Therefore, the perimeter \(P = 20 + 20\sqrt{2}\). Both statements together are sufficient.
Answer: C