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Statements (1) and (2) combined are insufficient. \(ABCD\) can be a rhombus but it can also be a kite-shaped figure. The diagonals of this figure form a cross, and S2 holds because of the symmetry (\(AB = BC\) and \(CD = AD\)).
Statements (1) and (2) combined are insufficient. \(ABCD\) can be a rhombus but it can also be a kite-shaped figure. The diagonals of this figure form a cross, and S2 holds because of the symmetry (\(AB = BC\) and \(CD = AD\)).
Answer: E
Bunuel HI , ABCD can also be a square,correct me if i'm wrong
Statements (1) and (2) combined are insufficient. \(ABCD\) can be a rhombus but it can also be a kite-shaped figure. The diagonals of this figure form a cross, and S2 holds because of the symmetry (\(AB = BC\) and \(CD = AD\)).
Answer: E
Bunuel HI , ABCD can also be a square,correct me if i'm wrong
Bunuel IF the condition 1 read that the AC is a perpendicular bisector of BD, would that have been enough to conclude that the figure was a rhombus ( considering square is also a special type of rhombus ) ? Will the diagonals of the a kite shaped figure also bisect each other at 90 degrees ?
Statements (1) and (2) combined are insufficient. \(ABCD\) can be a rhombus but it can also be a kite-shaped figure. The diagonals of this figure form a cross, and S2 holds because of the symmetry (\(AB = BC\) and \(CD = AD\)).
Answer: E
Bunuel HI , ABCD can also be a square,correct me if i'm wrong
Yes, it can be a square too.
Isn't it true that every square is a in fact a rhombus?
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. hi,
In a rhombus diagonals bisect each other at 90 degree. in statement one we are told that the diagonals bisect each other at 90 degree. then it must be a rhombus. even a kite shaped figure is a rhombus. correct me if im wrong.
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. hi,
In a rhombus diagonals bisect each other at 90 degree. in statement one we are told that the diagonals bisect each other at 90 degree. then it must be a rhombus. even a kite shaped figure is a rhombus. correct me if im wrong.
Yes, you are wrong.
RHOMBUS - a quadrilateral in which all four sides are congruent. KITE - a quadrilateral in which each pair of consecutive sides are congruent, but opposite sides are not congruent.
_________________
The existing explanations doesn't seem sufficient to me!
From statement 1,
We know that the diagram may be a rectangle/rhombus/square, hence insufficient.
Statement 2 also says the same since
AB+CD=BC+AD applies for all the three.
Is my reasoning correct?
Bunuel can you pls help me with this one!
No. All squares and rectangle, are rhombi. This is not the reason the answer is E. The point is that ABCD could be a kite, so NOT a rhombus.
Both kite and rhombus have the diagonals perpendicular to each other and the sum of the opposite sides equal to each other. So, ABCD can be a kite or a rhombus. Look at the diagram below:
The existing explanations doesn't seem sufficient to me!
From statement 1,
We know that the diagram may be a rectangle/rhombus/square, hence insufficient.
Statement 2 also says the same since
AB+CD=BC+AD applies for all the three.
Is my reasoning correct?
Bunuel can you pls help me with this one!
No. All squares and rectangle, are rhombi. This is not the reason the answer is E. The point is that ABCD could be a kite, so NOT a rhombus.
Both kite and rhombus have the diagonals perpendicular to each other and the sum of the opposite sides equal to each other. So, ABCD can be a kite or a rhombus. Look at the diagram below:
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60% (00:51) correct 
