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Bunuel
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Bunuel
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Ralphcuisak
Bunuel , I approximated the denominator as 2 and chose D as answer.It did strike that it would be a little lower than 2 as the denominator is a little over 2 but generally we approximate like i did earlier.So did we go into so much detail because the answer choices were in detail too?

Yes, the options are very close to each other so you should approximate with more precision.
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Hi,

I don't understand the explanation. Why and how we are transforming the equation like that?

Isn't it faster to do it like me:

I just multiplied the equation by 1000, so then there is 4000/2001= and it is very easy to solve.

Thank you
Max
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MaxKirchmayer
Hi,

I don't understand the explanation. Why and how we are transforming the equation like that?

Isn't it faster to do it like me:

I just multiplied the equation by 1000, so then there is 4000/2001= and it is very easy to solve.

Thank you
Max

Hi Max,

To make this calculation easier let's round down 2.001 to 2.

Then it will be 4/2 = 2

But, we know that the larger the denominator, the smaller is the number.

Comparing: 4/2.001 is a little bit smaller than 4/2.

This way, the answer choice has to be a little bit smaller than 2.

The answer is 1.999 ( C ).

I hope it helps!

Thanks, Ale :-)
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Hi Bunuel!

Thank you for the explanation. Even though I understood, I felt difficulty replicating the calculation for other similar questions. What material do you suggest I review for concept fixing?
Bunuel
Official Solution:

Which of the following is closest to \(\frac{4}{2.001}\)?

A. 1.997
B. 1.998
C. 1.999
D. 2.000
E. 2.001


The answer options are extremely close to each other, necessitating a very precise calculation. We can't simply round off 2.001 to 2 and assert that \(\frac{4}{2.001}\) is closest to 2 from the options given, due to this small difference.

Let's express 2.001 as 2 + 0.001 and multiply both the numerator and the denominator by the conjugate, 2 - 0.001:

\(\frac{4}{2.001}=\)

\(=\frac{4}{2+0.001}=\)

\(=\frac{4(2-0.001)}{(2+0.001)(2-0.001)}=\)

\(=\frac{4(2-0.001)}{4-0.001^2}\).

Now, \(0.001^2=0.000001\) is a very small number. Compared to 4, this value is practically negligible (do note that while we couldn't ignore 0.001 earlier, we can overlook 0.000001 now because it is 1000 times smaller than 0.001). Hence, we can approximate the equation as:

\(\frac{4(2-0.001)}{4-0.001^2} \approx \)

\(\approx \frac{4(2-0.001)}{4}=\)

\(= 2-0.001 =\)

\(=1.999\).

Therefore, \(\frac{4}{2.001}\) is closest to 1.999 among the provided options.


Answer: C
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eolivera89
Hi Bunuel!

Thank you for the explanation. Even though I understood, I felt difficulty replicating the calculation for other similar questions. What material do you suggest I review for concept fixing?

This question mainly tests number sense and algebraic manipulation. The best way to improve is through consistent practice and analysis of similar problems.
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