Got it
Bunuel! Thank you so much. I absolutely need to read the question very closely. I seem to be missing a lot when reading/solving 600-700 level questions
I now understand that this is how it pans out
Given = \(x^{x^{x^{...}}}\) = 2 \(-----> (1).\)
= \(x^{(x^{x^{...}})}\) = 2
Since the terms in the bracket goes on for infinity, it is actually the same as (1). Substituting
= \(x^2\) = 2
The question says \(X > 0\)
So, finally we get x = \(\sqrt{2}\)
Thanks also for the similar questions for practice!
Bunuel wrote:
susheelh wrote:
Hello
Bunuel,
I too have the same question as
Xavipersonal. How does the expression in bracker of \(x^{(x^{x^{...}})}\) end up as 2? Is this some kind of a rule?
Thanks in advance for your answer!
Let me ask you: does the expression in brackets differ from the expression which equals to 2 in any way?
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