Got it

Bunuel! Thank you so much. I absolutely need to read the question very closely. I seem to be missing a lot when reading/solving 600-700 level questions

I now understand that this is how it pans out

Given = \(x^{x^{x^{...}}}\) = 2 \(-----> (1).\)

= \(x^{(x^{x^{...}})}\) = 2

Since the terms in the bracket goes on for infinity, it is actually the same as (1). Substituting

= \(x^2\) = 2

The question says \(X > 0\)

So, finally we get x = \(\sqrt{2}\)

Thanks also for the similar questions for practice!

Bunuel wrote:

susheelh wrote:

Hello

Bunuel,

I too have the same question as

Xavipersonal. How does the expression in bracker of \(x^{(x^{x^{...}})}\) end up as 2? Is this some kind of a rule?

Thanks in advance for your answer!

Let me ask you: does the expression in brackets differ from the expression which equals to 2 in any way?

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