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Here since x is negative we get the expression as \frac{2|x| + 6}{3 - (- x)} = \frac{2|x| + 6}{3 + x} , right ?

Bunuel
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If \(\frac{\sqrt{x^2}}{\sqrt[3]{x^3}}=-1\) and \(x \neq 0\), what is the value of \(\frac{2|x| + 6}{3 - x}\) ?

A. -2
B. 1
C. 2
D. 3
E. Cannot be determined from the given information­


\(\frac{\sqrt{x^2}}{\sqrt[3]{x^3}} = -1\) simplifies to \(\frac{|x|}{x} = -1\), which then yields \(|x| = -x\). This indicates that \(x\) must be negative. If \(x < 0\), then \(|x| = -x\), and thus we get \(\frac{-2x + 6}{3 - x} = \frac{2(3 - x)}{3 - x} = 2\).


Answer: C

Knowing that x is negative does not mean x should be replaced by -x. Instead, we replace |x| with -x when x is negative.
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I did not quite understand the solution. It is nor clear why |x|=-x ; I though the absolute value can't be negative...
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Bunuel
Official Solution:

If \(\frac{\sqrt{x^2}}{\sqrt[3]{x^3}}=-1\) and \(x \neq 0\), what is the value of \(\frac{2|x| + 6}{3 - x}\) ?

A. -2
B. 1
C. 2
D. 3
E. Cannot be determined from the given information­


\(\frac{\sqrt{x^2}}{\sqrt[3]{x^3}} = -1\) simplifies to \(\frac{|x|}{x} = -1\), which then yields \(|x| = -x\). This indicates that \(x\) must be negative. If \(x < 0\), then \(|x| = -x\), and thus we get \(\frac{-2x + 6}{3 - x} = \frac{2(3 - x)}{3 - x} = 2\).


Answer: C
I did not quite understand the solution. It is nor clear why |x|=-x ; I though the absolute value can't be negative...

We get |x| = -x from the equation |x|/x = -1. Multiply both sides by x (which is nonzero), and you get |x| = -x. This only holds when x is negative, since for negative values, |x| is equal to -x. For example, if x = -5, then |x| = 5 = -(-5), so the logic checks out.

Recall the property of the absolute value:

\(|x| = x\), when \(x \geq 0\);
\(|x| = -x\), when \(x < 0\).

You should brush-up fundamental on absolute value:

10. Absolute Value



For more check Ultimate GMAT Quantitative Megathread



Hope it helps.
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I did not quite understand the solution. I marked Option E. Cannot be determined from the given information­
Thinking that 3-x and 3-x cannot be divided, as x ≠ 3 is not mentioned]

But the mistake I made was that, since x is negative, x cannot be +3 anyway.
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TangyGlue
I did not quite understand the solution. I marked Option E. Cannot be determined from the given information­
Thinking that 3-x and 3-x cannot be divided, as x ≠ 3 is not mentioned]

But the mistake I made was that, since x is negative, x cannot be +3 anyway.
Yes, exactly. Since the given equation forces x < 0, x cannot equal 3. So 3 - x is definitely nonzero, and the cancellation is valid.
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