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11 Jun 2018, 03:23
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
59% (01:17) correct
41%
(01:14)
wrong
based on 44
sessions
History
Date
Time
Result
Not Attempted Yet
11 Jun 2018, 03:23
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Official Solution:
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 2 variables (x and y) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) and 2) together first.
Conditions 1) and 2):
Since \(x = -4y\) and \(x = y^3\), \(|x| = |-4y| = 4|y|\) and \(|x| = |y^3| = |y|^3\).
It follows that \(4|y| = |y|^3\).
Now,
\(4|y| = |y|^3\) ⇔ \(|y|^3 - 4|y| = 0\)
⇔ \(|y|(|y|^2- 4) = 0\)
⇔ \(|y|(|y|+2)(|y|-2) = 0\).
Since \(|y| ≠0\) and \(|y| ≠-2\), this implies that \(|y| = 2\).
It follows that \(|x| = 4*2 = 8\).
So, \(|x| > |y|\), and both conditions together are sufficient.
Since this is an absolute value question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.
Condition 1)
Since \(|x| = |-4y| = 4|y|\) and \(xy≠0, |x| = 4|y| > |y|\).
Condition 1) is sufficient.
Condition 2)
If \(x = 8\), then \(y = 2\), and the answer is 'yes'.
If \(x = 1\), then \(y = 1\), and the answer is 'no'.
Since we have obtained two different answers, condition 2) is not sufficient by CMT 2.
Therefore, A is the answer.
Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
Answer: A
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Since we have 2 variables (x and y) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) and 2) together first.
Conditions 1) and 2):
Since \(x = -4y\) and \(x = y^3\), \(|x| = |-4y| = 4|y|\) and \(|x| = |y^3| = |y|^3\).
It follows that \(4|y| = |y|^3\).
Now,
\(4|y| = |y|^3\) ⇔ \(|y|^3 - 4|y| = 0\)
⇔ \(|y|(|y|^2- 4) = 0\)
⇔ \(|y|(|y|+2)(|y|-2) = 0\).
Since \(|y| ≠0\) and \(|y| ≠-2\), this implies that \(|y| = 2\).
It follows that \(|x| = 4*2 = 8\).
So, \(|x| > |y|\), and both conditions together are sufficient.
Since this is an absolute value question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.
Condition 1)
Since \(|x| = |-4y| = 4|y|\) and \(xy≠0, |x| = 4|y| > |y|\).
Condition 1) is sufficient.
Condition 2)
If \(x = 8\), then \(y = 2\), and the answer is 'yes'.
If \(x = 1\), then \(y = 1\), and the answer is 'no'.
Since we have obtained two different answers, condition 2) is not sufficient by CMT 2.
Therefore, A is the answer.
Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
Answer: A
mslimcaoco
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09 Nov 2020, 10:14
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Can someone please explain
"Since x=−4yx=−4y and x=y3x=y3, |x|=|−4y|=4|y||x|=|−4y|=4|y| and |x|=|y3|=|y|3|x|=|y3|=|y|3."
"Since x=−4yx=−4y and x=y3x=y3, |x|=|−4y|=4|y||x|=|−4y|=4|y| and |x|=|y3|=|y|3|x|=|y3|=|y|3."
