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Updated on: 05 Aug 2018, 22:55
Originally posted by MathRevolution on 11 Jun 2018, 06:48.
Last edited by MathRevolution on 05 Aug 2018, 22:55, edited 1 time in total.
Last edited by MathRevolution on 05 Aug 2018, 22:55, edited 1 time in total.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:47) correct
36%
(01:40)
wrong
based on 28
sessions
History
Date
Time
Result
Not Attempted Yet
If 3x - y ≠ 0, what is the value of (x+3y)/(3x-y)?
1) \(x-2y = 1\)
2) \(x-2y = 0\)
1) \(x-2y = 1\)
2) \(x-2y = 0\)
11 Jun 2018, 06:49
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Official Solution:
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
When the question asks for a ratio, a fraction, a percent, a proportion or a rate, if one of conditions provides a ratio and the other condition provides a number, the condition with a ratio could be sufficient.
This question asks for a ratio.
Condition 1) provides a number and condition 2) provides the ratio, x/y = 2.
Thus, condition 2) is likely to be sufficient.
Condition 1) :
If \(x = 3\) and \(y = 1\), then \((x+3y)/(3x-y) = 6/8 = 3/4\)
If \(x = 5\) and \(y = 2\), then \((x+3y)/(3x-y) = 16/13\)
Since we do not obtain a unique answer, condition 1) is not sufficient.
Condition 2) :
Since \(x = 2y\), \((x+3y)/(3x-y) = 5y/5y = 1\).
Condition 2) is sufficient.
Therefore, B is the answer.
Answer: B
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
When the question asks for a ratio, a fraction, a percent, a proportion or a rate, if one of conditions provides a ratio and the other condition provides a number, the condition with a ratio could be sufficient.
This question asks for a ratio.
Condition 1) provides a number and condition 2) provides the ratio, x/y = 2.
Thus, condition 2) is likely to be sufficient.
Condition 1) :
If \(x = 3\) and \(y = 1\), then \((x+3y)/(3x-y) = 6/8 = 3/4\)
If \(x = 5\) and \(y = 2\), then \((x+3y)/(3x-y) = 16/13\)
Since we do not obtain a unique answer, condition 1) is not sufficient.
Condition 2) :
Since \(x = 2y\), \((x+3y)/(3x-y) = 5y/5y = 1\).
Condition 2) is sufficient.
Therefore, B is the answer.
Answer: B
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04 Aug 2018, 00:43
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MathRevolution
I have a doubt.
from condition 2) one solution for x and y can be x = y = 0
In this case original expression - (x+3y)/(3x-y) can not have answer.
Pl clarify.
Bunuel chetan2u ScottTargetTestPrep
