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15 Jan 2014, 02:52
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D
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91% (01:12) correct
9%
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Machine X runs at a constant rate and produces a lot consisting of 100 cans in 2 hours. How much less time would it take to produce the lot of cans if both Machines X and Y were run simultaneously?
(1) Both Machines X and Y produce the same number of cans per hour.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot.
(1) Both Machines X and Y produce the same number of cans per hour.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot.
15 Jan 2014, 02:52
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SOLUTION
Machine X runs at a constant rate and produces a lot consisting of 100 cans in 2 hours. How much less time would it take to produce the lot of cans if both Machines X and Y were run simultaneously?
Machine X produces 100 cans in 2 hours --> the rate of X is (rate) = (job)/(time) = 100/2 = 50 cans per hour.
(1) Both Machines X and Y produce the same number of cans per hour --> so we know both the rates of X and Y. Sufficient.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot. Since Machine X takes 2 hours to produce the lot, then both Machines X and Y would take 1 hour to produce the lot. Sufficient.
Answer: D.
Machine X runs at a constant rate and produces a lot consisting of 100 cans in 2 hours. How much less time would it take to produce the lot of cans if both Machines X and Y were run simultaneously?
Machine X produces 100 cans in 2 hours --> the rate of X is (rate) = (job)/(time) = 100/2 = 50 cans per hour.
(1) Both Machines X and Y produce the same number of cans per hour --> so we know both the rates of X and Y. Sufficient.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot. Since Machine X takes 2 hours to produce the lot, then both Machines X and Y would take 1 hour to produce the lot. Sufficient.
Answer: D.
16 Jan 2014, 02:17
Kudos
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Machine X runs at a constant rate and produces a lot consisting of 100 cans in 2 hours. How much less time would it take to produce the lot of cans if both Machines X and Y were run simultaneously?
(1) Both Machines X and Y produce the same number of cans per hour.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot.
Statement 1
Given : Rate of Y = Rate of X
So, X & Y together would take 1 hour, which is half of 2 hours.
Thus, it would take one hour less time if X & Y both were run together ......Sufficient.
Statement 2
Given: To produce same lot of cans, duration of time that X run = 2 *(duration of time that X & Y together run)
Or, Rate of X = ( 1/2) Combined Rate of X & Y
Since, X takes 2 hours, the statement (2) is sufficient to answer that it would take one hour less time if X & Y both were run together.
Answer: (D)
(1) Both Machines X and Y produce the same number of cans per hour.
(2) It takes Machine X twice as long to produce the lot of cans as it takes Machines X and Y running simultaneously to produce the lot.
Statement 1
Given : Rate of Y = Rate of X
So, X & Y together would take 1 hour, which is half of 2 hours.
Thus, it would take one hour less time if X & Y both were run together ......Sufficient.
Statement 2
Given: To produce same lot of cans, duration of time that X run = 2 *(duration of time that X & Y together run)
Or, Rate of X = ( 1/2) Combined Rate of X & Y
Since, X takes 2 hours, the statement (2) is sufficient to answer that it would take one hour less time if X & Y both were run together.
Answer: (D)
