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sunita123
Hi Chetan2u
I did not understand this part "x+z=2y??"
should not it be, y= x+y+z/3?



chetan2u
Mani, Sani and Karna have x, y and z number of chocolates respectively. Does Sani have the average of the total number of chocolates among all three?

Is x+z=2y??

(1) y is 20% more than z and 25% less than x.
Since it gives us a ratio between 3, should be sufficient..
Let z=100, y=120% of 100=120
Also y=75% of X.....120=75% of X
X=120*4/3=160
So 100,120,160
Y is not the average
Sufficient

(2) x = 32.
Nothing about others
Insufficient

A

hi..

it is same..
\(y=\frac{x+y+z}{3}.........3y=x+y+z........2y=x+z\)
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