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Marie has twice as many brothers as sisters. Her brother Max has the

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Bunuel
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Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   22 Nov 2018, 01:47
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Marie has twice as many brothers as sisters. Her brother Max has the same number of brothers as sisters. How many brothers and sisters are there?

A. 3
B. 5
C. 6
D. 7
E. 9
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D
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KarishmaB
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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   22 Nov 2018, 05:02
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Bunuel wrote:
Marie has twice as many brothers as sisters. Her brother Max has the same number of brothers as sisters. How many brothers and sisters are there?

A. 3
B. 5
C. 6
D. 7
E. 9


Max, a boy, has the same number of brothers and sisters.
So he could have
Case 1: 1 brother, 1 sister
Total: 2 boys, 1 girl
OR

Case 2: 2 brothers, 2 sisters
Total: 3 boys, 2 girls
OR

Case 3: 3 brothers, 3 sisters
Total: 4 boys, 3 girls
etc.

In any case, the total number of boys will be 1 more than the total number of girls.

Marie has twice as many brothers as sisters. In
Case 1, she has 2 brothers, 0 sisters - does not satisfy
Case 2, she has 3 brother, 1 sister - does not satisfy
Case 3, she has 4 brothers, 2 sisters - Satisfies. So there are total 4 brothers and 3 sisters i.e. 7

Answer (D)
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rahul6019
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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   22 Nov 2018, 08:20
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Let total number of sisters - S
Let total number of brothers - B

Mary has twice number of brothers than sisters -> 2(S-1) = B
Max has equal number of brothers and sisters -> B-1 = S

Equating both -> 2(S-1) = S+1 gives S = 3, B = 4

Total number = 7. Correct Answer is D.
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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   22 Nov 2018, 08:52
For Marie, 2(S-1) = B
For Max, B-1 = S => B = S+1

=> 2(S-1) = S+1
=> S = 3
And B = 3+1=4
Total = 7

Answer Choice D

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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   17 Nov 2022, 09:33
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Let total no. of sisters are S
And total no. of brothers are B
For Marie: B=2(S-1) (since Marie doesn’t count herself)
For Max: B-1=S (since Max doesn’t count himself)
Solving these eq. will give S=3 and B=4 so total 7

Hope it helps :)
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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink] New post   24 Jan 2024, 09:31
Bunuel wrote:
Marie has twice as many brothers as sisters. Her brother Max has the same number of brothers as sisters. How many brothers and sisters are there?
A. 3
B. 5
C. 6
D. 7
E. 9



Sol:

Say Marie has x sisters ==> S = x
and has 2x brothers ===> B = 2x

Total No. of siblings = x + 2x + 1 (1 for Marie)
T = 3x+1

As x has to be an integer, total shall be a multiple of 3 + 1

Only option-D satisfies. (3*2 + 1)
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Re: Marie has twice as many brothers as sisters. Her brother Max has the [#permalink]
24 Jan 2024, 09:31
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