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Bunuel
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there are 2 fractional marks between 2 integers...hence,,,between 13 and 16 there will be 6 marks

plus 13 and 16 will total of 8 marks,,,

ans 8
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There are 2 marks between every integer mark. So, there will be 2(16-13) = 6 marks between 13 and 16, if we add 2 integer marks 14 and 15, that would make it 8. Ans - D.
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marks between 13 & 16 will be equal to marks between 0 &3

as you can see in the figure total marks preceding 1 are 3 (do not include 1).
same as total no of marks preceding 2 will be 6 (do not include 2).
and same as total no of marks preceding 3 will be 9 (do not include 3).

now to get the no of marks between 0&3,we have to exclude 0 (3 is already excluded) and we will remain with 8 marks.

OA is 8

please hit kudo if you like the solution.
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Bunuel

Marks are equally spaced on a number line as shown above. How many marks would there be on this number line between the marks at 13 and 16?

(A) 3
(B) 6
(C) 7
(D) 8
(E) 9

We see that the distance or spacing between two consecutive marks is 1/3. Thus, we need to see how many 1/3s between 13 and 16. That is, how many 1/3s divide into the difference of 13 and 16:

(16 - 13)/(1/3) = 3 x 3 = 9

However, 9 is the number of “1/3" spacings between 13 and 16; the number of markings will be 1 less than the number of spacings. Thus, there are 8 marks between the marks at 13 and 16.

Alternate Solution:

Let’s count the number of marks, noting that there will not be marks at either 13 or 16.

13 13⅓ 13⅔ 14 14⅓ 14⅔ 15 15⅓ 15⅔ 16

We see that there are 8 marks.

Answer: D
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2 marks between 2 numbers ..between 13 &16
2*3=6 and 2 marks for 13 &14 .hence 8

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