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# Marty has a right circular cylindrical pool of diameter 12 feet and hi

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Math Expert
Joined: 02 Sep 2009
Posts: 58327
Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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30 Oct 2018, 03:21
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82% (01:32) correct 18% (01:35) wrong based on 39 sessions

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Marty has a right circular cylindrical pool of diameter 12 feet and his neighbor, Rusty, has a right circular cylindrical pool of diameter 18 feet. If the depths of the pools are equal, then the volume of water in Rusty's pool is how many times that in Marty's pool?

A. 1.5
B. 2.25
C. 2.5
D. 4
E. 4.25

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Re: Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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Updated on: 31 Oct 2018, 19:19
1
Volume of cylinder = pi*$$d^2$$*h/4

So ratio of volumes when height is same, is the ratio of the diameters.

Ratio = $$18^2$$/$$12^2$$ = $$(3/2)^2$$ = 9/4 = 2.25

Option B
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Originally posted by nkin on 30 Oct 2018, 12:30.
Last edited by nkin on 31 Oct 2018, 19:19, edited 1 time in total.
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Re: Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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31 Oct 2018, 18:25
Bunuel wrote:
Marty has a right circular cylindrical pool of diameter 12 feet and his neighbor, Rusty, has a right circular cylindrical pool of diameter 18 feet. If the depths of the pools are equal, then the volume of water in Rustys pool is how many times that in Martys pool?

A. 1.5
B. 2.25
C. 2.5
D. 4
E. 4.25

If we assume that the height of both pools is h, then the volume of Marty’s pool is π * 6^2 * h = 36πh, and the volume of Rusty’s pool is π * 9^2 * h = 81πh. Therefore, the volume of Rusty’s pool is 81πh/36πh = 81/36 = 9/4 = 2.25 times that of Marty’s pool.

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Re: Marty has a right circular cylindrical pool of diameter 12 feet and hi   [#permalink] 31 Oct 2018, 18:25
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