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Marty has a right circular cylindrical pool of diameter 12 feet and hi

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Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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New post 30 Oct 2018, 02:21
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Question Stats:

87% (01:12) correct 13% (01:17) wrong based on 23 sessions

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Marty has a right circular cylindrical pool of diameter 12 feet and his neighbor, Rusty, has a right circular cylindrical pool of diameter 18 feet. If the depths of the pools are equal, then the volume of water in Rusty`s pool is how many times that in Marty`s pool?

A. 1.5
B. 2.25
C. 2.5
D. 4
E. 4.25

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Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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New post Updated on: 31 Oct 2018, 18:19
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Volume of cylinder = pi*\(d^2\)*h/4

So ratio of volumes when height is same, is the ratio of the diameters.

Ratio = \(18^2\)/\(12^2\) = \((3/2)^2\) = 9/4 = 2.25

Option B
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Originally posted by nkin on 30 Oct 2018, 11:30.
Last edited by nkin on 31 Oct 2018, 18:19, edited 1 time in total.
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Re: Marty has a right circular cylindrical pool of diameter 12 feet and hi  [#permalink]

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New post 31 Oct 2018, 17:25
Bunuel wrote:
Marty has a right circular cylindrical pool of diameter 12 feet and his neighbor, Rusty, has a right circular cylindrical pool of diameter 18 feet. If the depths of the pools are equal, then the volume of water in Rusty`s pool is how many times that in Marty`s pool?

A. 1.5
B. 2.25
C. 2.5
D. 4
E. 4.25


If we assume that the height of both pools is h, then the volume of Marty’s pool is π * 6^2 * h = 36πh, and the volume of Rusty’s pool is π * 9^2 * h = 81πh. Therefore, the volume of Rusty’s pool is 81πh/36πh = 81/36 = 9/4 = 2.25 times that of Marty’s pool.

Answer: B
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Re: Marty has a right circular cylindrical pool of diameter 12 feet and hi &nbs [#permalink] 31 Oct 2018, 17:25
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Marty has a right circular cylindrical pool of diameter 12 feet and hi

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