Hey,

PFB the official solution

It is given that

BD is the median of the triangle ABC.

From the given information we can conclude that:

• Area of Triangle ABD = Area of Triangle BDC

Which is equal to,

• Area of Triangle FEB + Area of Quadrilateral FEAD = Area of Triangle BFC + Area of Triangle FDC…. (i)

We are also given the following information –

• Area of BFC = \(6 cm^2\)

• Area of Quadrilateral FEAD = \(18cm^2\)

• And area of FDC: Area of FEB = 3: 2 o Let us consider the area of FDC and FEB to be \(3x\) and \(2x\) respectively.

Let us substitute the above values in equation (i)

• Area of Triangle FEB + Area of Quadrilateral FEAD = Area of Triangle BFC + Area of Triangle FDC o \(2x + 18 = 6 + 3x\)

o \(x = 12 cm^2\)

• Thus the Area of Triangle FDC = \(3x = 36 cm^2\)

Hence the

correct answer option is DThanks,

Saquib

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