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Updated on: 15 Dec 2016, 23:50
Originally posted by EgmatQuantExpert on 11 Dec 2016, 08:29.
Last edited by EgmatQuantExpert on 15 Dec 2016, 23:50, edited 1 time in total.
Last edited by EgmatQuantExpert on 15 Dec 2016, 23:50, edited 1 time in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
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Question Stats:
72% (02:47) correct
28%
(03:03)
wrong
based on 540
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Mastering Important Concept on Triangles – III - Question #1
In the given figure, BD is the median of triangle ABC and the lines BD and CE intersect at point F. If the area of triangle BFC is \(6cm^2\) and area of the quadrilateral FEAD is \(18cm^2\). Find the area of triangle FDC, if the ratio of the area of triangle FDC and triangle FEB is \(3:2\).
Answer Choices
Key concepts on Triangles are explained in detail in the following posts:
1. Mastering Important Concepts Tested By GMAT in Triangle - I
2. Mastering Important Concepts Tested By GMAT in Triangle - II
3.Mastering Important Concepts Tested By GMAT in Triangle - III
Detailed solution will be posted soon.
Thanks,
Saquib
Quant Expert
e-GMAT
In the given figure, BD is the median of triangle ABC and the lines BD and CE intersect at point F. If the area of triangle BFC is \(6cm^2\) and area of the quadrilateral FEAD is \(18cm^2\). Find the area of triangle FDC, if the ratio of the area of triangle FDC and triangle FEB is \(3:2\).
Answer Choices
- a. \(12 cm^2\)
b. \(18 cm^2\)
c. \(24 cm^2\)
d. \(36 cm^2\)
e. \(42 cm^2\)
Key concepts on Triangles are explained in detail in the following posts:
1. Mastering Important Concepts Tested By GMAT in Triangle - I
2. Mastering Important Concepts Tested By GMAT in Triangle - II
3.Mastering Important Concepts Tested By GMAT in Triangle - III
Detailed solution will be posted soon.
Thanks,
Saquib
Quant Expert
e-GMAT
Updated on: 15 Dec 2016, 23:49
Originally posted by EgmatQuantExpert on 11 Dec 2016, 08:31.
Last edited by EgmatQuantExpert on 15 Dec 2016, 23:49, edited 1 time in total.
Last edited by EgmatQuantExpert on 15 Dec 2016, 23:49, edited 1 time in total.
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Hey,
PFB the official solution
It is given that BD is the median of the triangle ABC.
From the given information we can conclude that:
We are also given the following information –
Let us substitute the above values in equation (i)
Hence the correct answer option is D
Thanks,
Saquib
Quant Expert
e-GMAT
PFB the official solution
It is given that BD is the median of the triangle ABC.
From the given information we can conclude that:
- • Area of Triangle ABD = Area of Triangle BDC
- • Area of Triangle FEB + Area of Quadrilateral FEAD = Area of Triangle BFC + Area of Triangle FDC…. (i)
We are also given the following information –
- • Area of BFC = \(6 cm^2\)
• Area of Quadrilateral FEAD = \(18cm^2\)
• And area of FDC: Area of FEB = 3: 2
- o Let us consider the area of FDC and FEB to be \(3x\) and \(2x\) respectively.
Let us substitute the above values in equation (i)
- • Area of Triangle FEB + Area of Quadrilateral FEAD = Area of Triangle BFC + Area of Triangle FDC
- o \(2x + 18 = 6 + 3x\)
o \(x = 12 cm^2\)
• Thus the Area of Triangle FDC = \(3x = 36 cm^2\)
Hence the correct answer option is D
Thanks,
Saquib
Quant Expert
e-GMAT
General Discussion
vivekkumar987
GMAT 1: 590 Q46 V25
Posts: 96
14 Dec 2016, 22:14
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Since BD is median , The area of triangle BDA= Area of triangle BDC
The area of triangle BDA= Area of triangle BDC
Area of BFE+ Area EFAD = Area BFC+ Area CFD
2x + 18 = 3x+ 6
X= 12.
we need 3x = 36 cm^2
The area of triangle BDA= Area of triangle BDC
Area of BFE+ Area EFAD = Area BFC+ Area CFD
2x + 18 = 3x+ 6
X= 12.
we need 3x = 36 cm^2
