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Math Revolution GMAT Instructor
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19 Nov 2017, 18:33
[GMAT math practice question] 27 percent of the students at a certain school are boys who are enrolled in an advanced math class. If 40 percent of the boys at the school are enrolled in the advanced math class, what percentage of all students at the school are boys? A. 25% B. 30% C. 35% D. 40% E. 45% => Attachment:
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(45s/100s)*100 = 45 % Therefore, the answer is E. Answer : E
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Re: Math Revolution Approach (PS)
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22 Nov 2017, 19:53
[GMAT math practice question] If 0<2x+3y<50 and 50<3x+2y<0, then which of the following must be true? I. x>0 II. y>0 III. x<y A. I only B . II only C. III only D. I and III E. I, II, and III => When we add the two inequalities 0<2x+3y<50 and 50<3x+2y<0, we obtain 50<5x+5y<50, or 20<2x2y< 20. Statement I. Adding the two inequalities 50<3x+2y<0 and 20<2x2y< 20 yields 70<x<20. So x may not be greater than zero. Statement I may not be true. Statement II. Adding the two inequalities 0<2x+3y<50 and 20<2x2y< 20 yields 20<y<70. So y may not be greater than zero. Statement II may not be true, either. Statement III. Since 0<2x+3y<50 is equivalent to 50<2x3y<0 and 50<3x+2y<0, adding the two inequalities yields 100<xy<0. This implies that x < y. Statement III must be true. Therefore, the answer is C. Answer : C
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Re: Math Revolution Approach (PS)
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22 Nov 2017, 19:55
[GMAT math practice question] If r is an integer, and 700 < 10!/(10r)!<1,000, then r= A. 1 B. 2 C. 3 D. 4 E. 5 => Note that 10!/(10r)! = 10 * (101) * … * (10r+1). Test different values of r: r=1 : 10 r=2 : 10 * 9 = 90 r=3 : 10 * 9 * 8 = 720 r=4 : 10 * 9 * 8 * 7 = 5040 Therefore, r = 3. The answer is C. Answer: C
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24 Nov 2017, 01:27
[GMAT math practice question] i, j, and k are nonnegative integers such that i+j+k=3. If p, q, and r are three fixed, but different, prime numbers, how many different values of p^iq^jr^k are possible? A. 8 B. 9 C. 10 D. 11 E. 12 => The number of possible values of p^iq^jr^k is equal to the number of solutions of the equation i + j + k = 3. The solution set of the equation i + j + k = 3 includes all permutations of (3,0,0), (2,1,0), and (1,1,1). The number of permutations of (3,0,0) is 3!2! = 3. The number of permutations of (2,1,0) is 3! = 6. The number of permutations of (1,1,1) is 1. Therefore, the number of solutions of the equation i+j+k=3 is 3 + 6 + 1 = 10. Therefore, the answer is C. Answer: C
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26 Nov 2017, 18:28
[GMAT math practice question] If (x+2)!/x! = 72, then x= A. 6 B. 7 C. 8 D. 9 E. 10 => Now, 72= (x+2)!/x! = [x!*(x+1)*(x+2)]/x! =(x+1)(x+2). So, x2 + 3x + 2 = 72 x2 +3x – 70 = 0 (x7)(x+10) = 0 x = 7 or x = 10. Since factorials are only defined for x ≥0, x = 7. Therefore, the answer is B. Answer: B
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26 Nov 2017, 18:32
[GMAT math practice question] A circle with center (6,8) and radius 2 lies in the standard xyplane. What is the shortest distance between the origin and the points of the circle? A. 4 B. 6 C. 8 D. 10 E. 12 Attachment:
A.png [ 7.44 KiB  Viewed 557 times ]
The distance between the origin and the center of the circle is 10=√(6^2+4^2). Since the radius of the circle is 2, the point of the circle closest to the origin lies along the line joining the center to the origin, and so has distance 10 – 2 = 8 from the origin. Therefore, the answer is C. Answer : C
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29 Nov 2017, 00:28
[GMAT math practice question] Attachment:
A.png [ 3.44 KiB  Viewed 545 times ]
In the number line above, the ticks are evenly spaced. Which point represents 2^{10}? A. A B. B C. C D. D E. E => The distance between each pair of consecutive ticks is 2^9 – 2^8 = 2^8(21) = 2^8. Find the values of each point: A = 2^9 + 2^8. B = A + 2^8 = 2^9 + 2^8 + 2^8 = 2^9 + 2*2^8 = 2^9 + 2^9 = 2*2^9 = 2^{10}. Therefore, the answer is B. Answer : B
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30 Nov 2017, 01:29
[GMAT math practice question] For positive integers x and y, x@y is defined by x@y=(x+y)/xy. If a, b, and c are positive integers, what is the value of 1/a@1/(1/b@1/c)? A. a+b+c B. 1/abc C. 1/(a+b+c) D. 1/(ab+bc+ca) E. 3/abc => We can simplify the definition of the operation in the following way: x@y=(x+y)/xy = x/(xy) + y/(xy) = 1/x+1/y. So, 1/a@1/(1/b@1/c) = a + (1/b @1/ c) = a + ( b + c ). Therefore, the answer is A. Answer: A
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01 Dec 2017, 01:13
[GMAT math practice question] Nov. 18th fell on a Thursday in 1999. On which day did Nov. 18th fall in 2005? A. Tuesday B. Wednesday C. Thursday D. Friday E. Saturday => If a year is divisible by 400, it is a leap year. If a year is divisible by 100, but not divisible by 400, it is not a leap year. If a year is divisible by 4, but not divisible by 100, it is a leap year. The day on which a particular date falls will be shifted by two days from one year to the next if the next year is a leap year, and by one day from one year to the next if the next year is not a leap year. For example, Nov. 18th fell on a Thursday in 1999, and a Saturday in 2000 since 2000 was a leap year. It fell on a Saturday in 2000, and a Sunday in 2001 since 2001 was not a leap year. As there were two leap years (2000 and 2004) between 1999 and 2005, Nov. 18th shifted by 8 days over the 6year period. If a date is shifted by 7 days, it will fall on the same day of the week. So, the net effect was to shift Nov. 18th by one day. Therefore, Nov 18th fell on a Friday in 2005, and the answer is D. Answer: D
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03 Dec 2017, 18:41
[GMAT math practice question] If m>n>0, x=m^2+n^2, and y=2mn, what is the value of √x^2√y^2 in terms of m and n? A. m^2+n^2 B. 2m^2+n^2 C.m^2+2n^2 D. n^2m^2 E. m^2n^2 => Plugging in the expressions for x and y, and expanding gives: x^2 – y^2 = (m^2+n^2)^2 – (2mn)^2 = m^4 2m^2n^2 + n^4 = (m^2n^2)^2. So, since m^2 > n^2, √x^2√y^2=√(m^2n^2)^2=m^2n^2=m^2n^2. Therefore, the answer is E. Answer: E
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03 Dec 2017, 18:43
[GMAT math practice question] When 2 fair dice are tossed, what is the probability that the difference between the 2 numbers that land face up will be 3? A. 1/6 B. 1/3 C. 1/2 D. 2/3 E. 5/6 => 6 pairs of numbers with this property can appear on the dice: (1,4), (4,1), (2,5), (5,2), (3,6) and (6,3). The total number of outcomes from rolling two dice is 36. Thus, the probability that the two numbers will have a difference of 3 is 6/36 = 1/6. Therefore, the answer is A. Answer : A
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06 Dec 2017, 01:10
[GMAT math practice question] How many real numbers x satisfy x34=4? A. 1 B. 2 C. 3 D. 4 E. 5 =>  x3  4  = 4 ⇔ x3  4= ± 4 ⇔ x3 = 4 ± 4 ⇔ x3 = 8 or x3 = 0 ⇔ x3 = ±8 or x3 = 0 ⇔ x = 3 ± 8 or x = 3 ⇔ x = 11, x = 5 or x = 3 The equation has 3 solutions. Therefore, the answer is C. Answer : C
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07 Dec 2017, 01:03
[GMAT math practice question] Which of the following is the closest to 11^59^5 – 2(10^5)? A. 10^2 B. 10^7 C. 10^8 D. 10^9 E. 10^{10} => 11^59^5 – 2(10^5) ≒ 10^510^5 – 2(10^5) = 10^{10} – 2(10^5) ≒ 10^{10} Therefore, the answer is E. Answer: E
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Re: Math Revolution Approach (PS)
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08 Dec 2017, 01:08
[GMAT math practice question] What is the remainder when 7^{30} is divided by 100? A. 19 B. 29 C. 39 D. 49 E. 59 => The tens digit of 7^k cycles through 0>4>4>0>0>….. The units digit of 7^k cycles through 7>9>3>1>7>….. Since 30=4(7)+2, 7^{30}=7^{4(7)+2} ends in 49. Therefore, the answer is D. Answer: D
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Re: Math Revolution Approach (PS)
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08 Dec 2017, 02:08
MathRevolution wrote: [GMAT math practice question]
n number of people are attending a meeting. All of them shake hands with each other. If all attendees shake hands 210 times, what is the value of n?
A. 15 B. 19 C. 20 D. 21 E. 25
=>
nC2 = n(n1)/2 = 210 n(n1) = 420 n(n1) – 420 = 0 n^2 – n – 420 = 0 (n21)(n+20) = 0 n = 21 or n = 21 n = 21 since n must be positive.
Answer: D Hey Hey man, how Sent from my Redmi Note 4 using GMAT Club Forum mobile app



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Re: Math Revolution Approach (PS)
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10 Dec 2017, 18:14
[GMAT math practice question] If n is the sum of the first 40 positive integers, what is the greatest prime factor of n? A. 11 B. 29 C. 31 D. 41 E. 53 => n = 1 + 2 + … + 40 = 40∙41/2 = 20∙41 = 2^2∙5∙41. Thus the greatest prime factor of n is 41. Therefore, the answer is D. Answer: D
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10 Dec 2017, 18:15
[GMAT math practice question] When n is divided by 5, the remainder is 3, and when n is divided by 6, the remainder is 3. What is the remainder when the smallest possible integer value of n is divided by 7? A. 0 B. 1 C. 2 D. 3 E. 4 => Plugging in numbers is the recommended approach for remainder questions. The integers that have a remainder of 3 when they are divided by 5 are 3, 8, 13, 18, 23, 28, 33, 38, … The integers that have a remainder of 3 when they are divided by 6 are 3, 9, 15, 21, 27, 33, 39, 38, … The smallest integer n that occurs in both lists is 38. Since 38 = 7 ∙5 + 3, this value of n has a remainder of 3 when it is divided by 7. Therefore, the answer is D. Answer : D
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13 Dec 2017, 00:40
[GMAT math practice question] Attachment:
pic.png [ 1.95 KiB  Viewed 482 times ]
If the distances between consecutive ticks in the above number line are the same, which of the following points represents 2^11? A. A B. B C. C D. D E. E => Let d be the distance between consecutive ticks. Then 2d = 2^10 – 2^9 = 2*2^9 – 2^9 = 2^9 d=2^8. Since 2^11 – 2^10 = 2^32^8 – 2^22^8 = 8(2^8)– 4(2^8)= 4(2^8)= 4d, 2^11 is the fourth point from 2^10, which is D. Therefore, the answer is D. Answer : D
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14 Dec 2017, 02:14
[GMAT math practice question] Attachment:
12.png [ 1.33 KiB  Viewed 470 times ]
Points A, B, C, and D lie on the number line as shown in the figure above. If AC=BD and AB=BC/5, what is the value of C? A. 7/14 B. 8/14 C. 9/14 D. 10/14 E. 11/14 => Suppose d is the distance between A and B. Then CD = d and BC = 5d. Thus, AD = d + 5d + d = 7d. Since A = ½ and D = 2/3, 7d = 2/3 – 1/2 = 4/6 – 3/6 = 1/6, and d = 1/42. So, D – C = 1/42, and C = 2/3 – 1/42 = 28/42 – 1/42 = 27/42 = 9/14. Therefore, the answer is C. Answer: C
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Math Revolution GMAT Instructor
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Re: Math Revolution Approach (PS)
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18 Dec 2017, 00:27
[GMAT math practice question] If 3^x>100, which of the following must be true? I. x>3 II. x>4 III. x>5 A. I only B. II only C. III only D. I and II only E. I, II, and III => Since 3^x>100 and 100>81=3^4, x > 4. This implies that x > 3, too. 3^5 = 243 > 100, so statement III may not be true. As only statements I and II are true, the answer is D. Answer: D
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