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May 0510:00 AM PDT
-11:00 AM PDT
GMAT Inequalities is a high-frequency topic in GMAT Quant, but many students struggle because the concepts behave differently from standard algebra. Understanding the right rules, patterns, and edge cases can significantly improve both speed and accuracy.- May 06
08:30 AM PDT
-09:30 AM PDT
In Episode 3 of our GMAT Ninja Critical Reasoning series, we tackle Discrepancy, Paradox, and Explain an Oddity questions. You know the feeling: the passage gives you two facts that seem completely contradictory.... - May 08
08:00 AM PDT
-08:30 AM PDT
Join the special YouTube live-stream for selecting the winners of GMAT Club MBA Scholarships sponsored by Juno live. Watch who gets these coveted MBA scholarships offered by GMAT Club and Juno.
19 Nov 2017, 18:33
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[GMAT math practice question]
27 percent of the students at a certain school are boys who are enrolled in an advanced math class. If 40 percent of the boys at the school are enrolled in the advanced math class, what percentage of all students at the school
are boys?
A. 25%
B. 30%
C. 35%
D. 40%
E. 45%
=>
11.20.png [ 3.16 KiB | Viewed 2643 times ]
(45s/100s)*100 = 45 %
Therefore, the answer is E.
Answer : E
27 percent of the students at a certain school are boys who are enrolled in an advanced math class. If 40 percent of the boys at the school are enrolled in the advanced math class, what percentage of all students at the school
are boys?
A. 25%
B. 30%
C. 35%
D. 40%
E. 45%
=>
Attachment:
11.20.png [ 3.16 KiB | Viewed 2643 times ]
(45s/100s)*100 = 45 %
Therefore, the answer is E.
Answer : E
22 Nov 2017, 19:53
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[GMAT math practice question]
If 0<2x+3y<50 and -50<3x+2y<0, then which of the following must be true?
I. x>0
II. y>0
III. x<y
A. I only
B . II only
C. III only
D. I and III
E. I, II, and III
=>
When we add the two inequalities 0<2x+3y<50 and -50<3x+2y<0, we obtain -50<5x+5y<50, or -20<-2x-2y< 20.
Statement I.
Adding the two inequalities -50<3x+2y<0 and -20<-2x-2y< 20 yields -70<x<20.
So x may not be greater than zero.
Statement I may not be true.
Statement II.
Adding the two inequalities 0<2x+3y<50 and -20<-2x-2y< 20 yields -20<y<70.
So y may not be greater than zero.
Statement II may not be true, either.
Statement III.
Since 0<2x+3y<50 is equivalent to -50<-2x-3y<0 and -50<3x+2y<0, adding the two inequalities yields
-100<x-y<0. This implies that x < y.
Statement III must be true.
Therefore, the answer is C.
Answer : C
If 0<2x+3y<50 and -50<3x+2y<0, then which of the following must be true?
I. x>0
II. y>0
III. x<y
A. I only
B . II only
C. III only
D. I and III
E. I, II, and III
=>
When we add the two inequalities 0<2x+3y<50 and -50<3x+2y<0, we obtain -50<5x+5y<50, or -20<-2x-2y< 20.
Statement I.
Adding the two inequalities -50<3x+2y<0 and -20<-2x-2y< 20 yields -70<x<20.
So x may not be greater than zero.
Statement I may not be true.
Statement II.
Adding the two inequalities 0<2x+3y<50 and -20<-2x-2y< 20 yields -20<y<70.
So y may not be greater than zero.
Statement II may not be true, either.
Statement III.
Since 0<2x+3y<50 is equivalent to -50<-2x-3y<0 and -50<3x+2y<0, adding the two inequalities yields
-100<x-y<0. This implies that x < y.
Statement III must be true.
Therefore, the answer is C.
Answer : C
22 Nov 2017, 19:55
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[GMAT math practice question]
If r is an integer, and 700 < 10!/(10-r)!<1,000, then r=
A. 1
B. 2
C. 3
D. 4
E. 5
=>
Note that
10!/(10-r)! = 10 * (10-1) * … * (10-r+1).
Test different values of r:
r=1 : 10
r=2 : 10 * 9 = 90
r=3 : 10 * 9 * 8 = 720
r=4 : 10 * 9 * 8 * 7 = 5040
Therefore, r = 3.
The answer is C.
Answer: C
If r is an integer, and 700 < 10!/(10-r)!<1,000, then r=
A. 1
B. 2
C. 3
D. 4
E. 5
=>
Note that
10!/(10-r)! = 10 * (10-1) * … * (10-r+1).
Test different values of r:
r=1 : 10
r=2 : 10 * 9 = 90
r=3 : 10 * 9 * 8 = 720
r=4 : 10 * 9 * 8 * 7 = 5040
Therefore, r = 3.
The answer is C.
Answer: C
