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GMATH Teacher
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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11 Jan 2019, 06:28
MathRevolution wrote: [ Math Revolution GMAT math practice question] (function) In the \(xy\)plane, a circle has center \((0,0)\) and radius \(5\). Is the point \((r,s)\) inside or on the circle? \(1) 3 < r < 3\) \(2) 4 < s < 4\) \(\left( {r,s} \right)\,\,\,\mathop \in \limits^? \,\,\,\left\{ {\,\left( {x,y} \right)\,\,:\,\,{{\left( {x  0} \right)}^2} + {{\left( {y  0} \right)}^2} \leqslant {5^2}\,} \right\}\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\boxed{\,\,\,{r^2} + {s^2}\,\,\,\mathop \leqslant \limits^? \,\,\,25\,}\,\,\) \(\left( 1 \right)\,\,\,\,\left r \right < 3\,\,\,\left\{ \matrix{ \,{\rm{Take}}\,\,\left( {r,s} \right) = \left( {0,0} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr \,{\rm{Take}}\,\,\left( {r,s} \right) = \left( {0,6} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\, \hfill \cr} \right.\) \(\left( 2 \right)\,\,\,\left s \right < 4\,\,\,\,\left\{ \matrix{ \,\left( {{\mathop{\rm Re}\nolimits} } \right){\rm{Take}}\,\,\left( {r,s} \right) = \left( {0,0} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr \,{\rm{Take}}\,\,\left( {r,s} \right) = \left( {6,0} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\, \hfill \cr} \right.\) \(\left( {1 + 2} \right)\,\,\,\,\left\{ \matrix{ \,{r^2} = {\left r \right^2} < {3^2} \hfill \cr \,{s^2} = {\left s \right^2} < {4^2} \hfill \cr} \right.\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{r^2} + {s^2} < 25\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle\) This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio.
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)



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Math Revolution DS Expert  Ask Me Anything about GMAT DS
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11 Jan 2019, 07:09
MathRevolution wrote: [ Math Revolution GMAT math practice question] (geometry) \(x, y\) and \(z\) are the sides of the triangle shown and \(h\) is its height. Is the perimeter, \(x + y + z\) of the triangle greater than \(1\)? \(1) h = \frac{1}{2}\) \(2) x = y = \frac{1}{3}\) \(x + y + z\,\,\mathop > \limits^? \,\,\,1\) \(\left( 1 \right)\,\,\,\left\{ \matrix{ \,x\mathop > \limits^{\left( * \right)} \,\,\,h = {1 \over 2} \hfill \cr \,z\mathop > \limits^{\left( * \right)} \,\,\,h = {1 \over 2} \hfill \cr y > 0 \hfill \cr} \right.\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,x + y + z > 1\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle\) \(\left( 2 \right)\,\,\left\{ \matrix{ \,{\rm{figure}}\,\,{\rm{on}}\,\,{\rm{the}}\,\,{\rm{left}}\,\,\, \Rightarrow \,\,\,\,\,x + y + z\,\,\,\, < \,\,\,\,3\left( {{1 \over 3}} \right)\,\, = \,\,1\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,\left\langle {{\rm{NO}}} \right\rangle \hfill \cr \,{\rm{figure}}\,\,{\rm{on}}\,\,{\rm{the}}\,\,{\rm{right}}\,\,\, \Rightarrow \,\,\,\,\,x + y + z\,\,\,\,\mathop < \limits^{{\rm{as}}\,{\rm{near}}\,\,{\rm{as}}\,\,{\rm{desired}}!} \,\,\,\,{2 \over 3} + {1 \over 3}\left( {\sqrt 2 } \right)\,\, = \,\,{{\sqrt 2 + 2} \over 3}\,\,\,\,\,\left[ { > \,\,\,1} \right]\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \hfill \cr} \right.\) The correct answer is therefore (A). This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio. P.S.: it is interesting to study the case in which D does not belong to the side BC!
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)



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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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13 Jan 2019, 16:52
MathRevolution wrote: [ Math Revolution GMAT math practice question] (geometry) \(x, y\) and \(z\) are the sides of the triangle shown and \(h\) is its height. Is the perimeter, \(x + y + z\) of the triangle greater than \(1\)? \(1) h = \frac{1}{2}\) \(2) x = y = \frac{1}{3}\) Attachment: 1.10.png => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. In a triangle, the sum of the lengths of two sides is always greater than the length of the other side. Thus, from triangle \(ABD\), we must have \(AB + BD > AD = h\), and from triangle \(ABD\), we must have \(AC + CD > AD = h\). If \(h = \frac{1}{2}\), then \(AB + BC + CA = AB + BD + DC + CA > \frac{1}{2} + \frac{1}{2} = 1.\) Condition 1) is sufficient. Condition 2): If \(AC = \frac{1}{2}\), then \(AB + BC + CA = \frac{1}{3} + \frac{1}{3} + \frac{1}{2} = \frac{7}{6} > 1\) and the answer is ‘yes’. If \(AC = \frac{1}{4}\), then \(AB + BC + CA = \frac{1}{3} + \frac{1}{3} + \frac{1}{4} = \frac{11}{12} < 1\) and the answer is ‘no’. Since it does not yield a unique solution, condition 2) is not sufficient. Therefore, the correct answer is A. Answer: A
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Math Revolution GMAT Instructor
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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13 Jan 2019, 17:00
Attachment:
1.14.png [ 22.82 KiB  Viewed 74 times ]
MathRevolution wrote: [ Math Revolution GMAT math practice question] (function) In the \(xy\)plane, a circle has center \((0,0)\) and radius \(5\). Is the point \((r,s)\) inside or on the circle? \(1) 3 < r < 3\) \(2) 4 < s < 4\) => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. The inequality satisfied by points inside or on the circle is \(r^2+s^2≤5^2=25\). Since we have \(2\) variables (\(r\) and \(s\)) and \(0\) equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. Conditions 1) & 2): Since \(3<r<3\) and \(4<s<4\), we have \(0≤r^2<3^2=9\) and \(0≤s^2<4^2=16\). Thus, \(0≤r^2+s^2<9+16=25\) and both conditions together are sufficient. Attachment:
1.14.png [ 22.82 KiB  Viewed 74 times ]
Therefore, the answer is C. Answer: C
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The oneandonly World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only $149 for 3 month Online Course" "Free Resources30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons  try it yourself"



Math Revolution GMAT Instructor
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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14 Jan 2019, 00:04
[ Math Revolution GMAT math practice question] (absolute value, geometry) Is \(a > b  c\)? \(1) cb < a\) \(2) a, b\), and \(c\) are the lengths of the \(3\) sides of a triangle.
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The oneandonly World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only $149 for 3 month Online Course" "Free Resources30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons  try it yourself"



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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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14 Jan 2019, 04:51
MathRevolution wrote: [ Math Revolution GMAT math practice question] (absolute value, geometry) Is \(a > b  c\)? \(1) cb < a\) \(2) a, b\), and \(c\) are the lengths of the \(3\) sides of a triangle. \(a\,\,\mathop > \limits^? \,\,b  c\) \(\left( 1 \right)\,\,\,a\,\, > \,\,\left {c  b} \right\,\,\, = \,\,\,\left {b  c} \right\,\,\,\, \ge \,\,\,b  c\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\) \(\left( 2 \right)\,\, \Rightarrow \,\,\left( 1 \right)\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\) The correct answer is therefore (D). This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio.
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6804
GPA: 3.82

Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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14 Jan 2019, 23:58
[ Math Revolution GMAT math practice question] (number properties) If \(x, y\) are integers, is \(x^2+x+y\) an odd integer? 1) \(x\) is an odd integer 2) \(y\) is an odd integer
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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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15 Jan 2019, 05:51
MathRevolution wrote: [ Math Revolution GMAT math practice question] (number properties) If \(x, y\) are integers, is \(x^2+x+y\) an odd integer? 1) \(x\) is an odd integer 2) \(y\) is an odd integer \(x,y\,\,{\text{ints}}\,\,\,\left( * \right)\) \({x^{\text{2}}} + x + y\,\, = \,\,\underbrace {x\left( {x + 1} \right)}_{\left( * \right)\,\,{\text{even}}} + y\,\,\mathop = \limits^? \,\,\,{\text{odd}}\,\,\,\,\,\,\,\,\, \Leftrightarrow \,\,\,\,\boxed{\,\,y\,\,\mathop = \limits^? \,\,\,{\text{odd}}\,\,}\) \(\left( 1 \right)\,\,x\,\,{\rm{odd}}\,\,\,\left\{ \matrix{ \,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {1,0} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{NO}}} \right\rangle \,\, \hfill \cr \,{\rm{Take}}\,\,\left( {x,y} \right) = \left( {1,1} \right)\,\,\,\, \Rightarrow \,\,\,\left\langle {{\rm{YES}}} \right\rangle \,\, \hfill \cr} \right.\) \(\left( 2 \right)\,\,y\,\,{\text{odd}}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\left\langle {{\text{YES}}} \right\rangle\) This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio.
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Fabio Skilnik :: GMATH method creator (Math for the GMAT)



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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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16 Jan 2019, 00:14
MathRevolution wrote: [ Math Revolution GMAT math practice question] (absolute value, geometry) Is \(a > b  c\)? \(1) cb < a\) \(2) a, b\), and \(c\) are the lengths of the \(3\) sides of a triangle. => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. Condition 1) is sufficient since it yields \(b – c ≤  b  c  =  c – b  < a.\) Condition 2) Since the sum of the lengths of two sides of a triangle is greater than the length of the third side, we must have \(a + c > b\). Thus, condition 2) is sufficient. Therefore, D is the answer. Answer: D FYI, Tip 1) of the VA method states that D is most likely to be the answer if conditions 1) and 2) provide the same information.
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The oneandonly World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only $149 for 3 month Online Course" "Free Resources30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons  try it yourself"



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Re: Math Revolution DS Expert  Ask Me Anything about GMAT DS
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16 Jan 2019, 00:15
[ Math Revolution GMAT math practice question] (number properties) If \(x\) and \(y\) are integers, is \(x^2y^2\) an even integer? 1) \(x^3y^3\) is an even integer 2) \(x+y\) is an even integer
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MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The oneandonly World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only $149 for 3 month Online Course" "Free Resources30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons  try it yourself"




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