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# Maxwell leaves his home and walks toward Brad's house at the same time

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Math Expert
Joined: 02 Sep 2009
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Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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06 Jun 2016, 03:21
00:00

Difficulty:

15% (low)

Question Stats:

81% (01:11) correct 19% (01:49) wrong based on 142 sessions

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Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad when they meet?

(A) 16
(B) 18
(C) 20
(D) 24
(E) 30

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Re: Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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06 Jun 2016, 10:23
4
1
Time taken = Total Distance / Relative Speed
Total Distance = 50 kms
Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4 = 10 kms/hr

Time taken = 50 / 10 = 5 hrs
Distance traveled by Brad = Brad's speed * time taken = 6 * 5 = 30 kms... Answer - E

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Joined: 27 May 2012
Posts: 668
Re: Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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26 Jul 2018, 02:12
1
Bunuel wrote:
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?

(A) 16
(B) 18
(C) 20
(D) 24
(E) 30

Dear Moderator ,
Came across this question while going through the forum, seems as though something is missing.
seems " When they meet is missing ".

Feel question should be as below :

Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad,when they both meet?

Hope you will look into this , and if required, will do the needful, thank you.
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Joined: 22 May 2016
Posts: 2353
Re: Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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27 Jul 2018, 15:12
stne wrote:
Dear Moderator ,
Came across this question while going through the forum, seems as though something is missing.
seems " When they meet is missing ".

Feel question should be as below :

Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad,when they both meet?

Hope you will look into this , and if required, will do the needful, thank you.

stne , thank you. Edited.
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Re: Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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30 Jul 2018, 10:50
Bunuel wrote:
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad when they meet?

(A) 16
(B) 18
(C) 20
(D) 24
(E) 30

We can let Maxwell’s time = t = Brad’s time. Furthermore, since distance = rate x time, Maxwell’s distance = 4t and Brad’s distance = 6t . Since their total distance is 50 km, we can create the following equation:

Maxwell’s distance + Brad’s distance = 50

4t + 6t = 50

10t = 50

t = 5

Thus, Brad has traveled 6(5) = 30 km when they meet.

Alternate Solution:

Since Brad and Maxwell are moving towards each other, the distance between the two is decreasing at a rate of 4 + 6 = 10 km/h. Since they are 50 km apart initially, they will meet after 50/10 = 5 hours. Thus, when they meet, Brad will have traveled 5 x 6 = 30 kilometers.

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Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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Updated on: 03 Aug 2018, 21:53
Since their speeds are in ratio 3:2 their distance travelled will also be in the ratio 3:2. (Since, Time is same for both of them).
So the distance travelled by Brad will be 3/5*50 =30.

Posted from my mobile device

Originally posted by Sherlock221b on 03 Aug 2018, 08:53.
Last edited by Sherlock221b on 03 Aug 2018, 21:53, edited 1 time in total.
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Re: Maxwell leaves his home and walks toward Brad's house at the same time  [#permalink]

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03 Aug 2018, 09:42
Bunuel wrote:
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad when they meet?

(A) 16
(B) 18
(C) 20
(D) 24
(E) 30

In this case we don't even need to calculate I think.
Brad's speed > Maxwell's speed --> distance traveled by Brad > distance traveled by Maxwell --> distance traveled by Brad will be more than 25 km (half of the total distance) when they meet.
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Re: Maxwell leaves his home and walks toward Brad's house at the same time &nbs [#permalink] 03 Aug 2018, 09:42
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