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24 Jan 2014, 03:57
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D
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Difficulty:
5%
(low)
Question Stats:
90% (01:00) correct
10%
(01:06)
wrong
based on 1645
sessions
History
Date
Time
Result
Not Attempted Yet
Members of a social club met to address 280 newsletters. If they addressed 1/4 of the newsletters during the first hour and 2/5 of the remaining newsletters during the second hour, how many newsletters did they address during the second hour?
(A) 28
(B) 42
(C) 63
(D) 84
(E) 112
(A) 28
(B) 42
(C) 63
(D) 84
(E) 112
24 Jan 2014, 03:57
Kudos
Bookmarks
SOLUTION
Members of a social club met to address 280 newsletters. If they addressed 1/4 of the newsletters during the first hour and 2/5 of the remaining newsletters during the second hour, how many newsletters did they address during the second hour?
(A) 28
(B) 42
(C) 63
(D) 84
(E) 112
1/4 of the newsletters were addressed during the first hour, thus 3/4 of the newsletters were NOT addressed during the first hour, which means that 3/4*280 = 210 were NOT addressed during the first hour. Therefore, 2/5*210 = 84 newsletters were addressed during the second hour.
Answer: D.
Members of a social club met to address 280 newsletters. If they addressed 1/4 of the newsletters during the first hour and 2/5 of the remaining newsletters during the second hour, how many newsletters did they address during the second hour?
(A) 28
(B) 42
(C) 63
(D) 84
(E) 112
1/4 of the newsletters were addressed during the first hour, thus 3/4 of the newsletters were NOT addressed during the first hour, which means that 3/4*280 = 210 were NOT addressed during the first hour. Therefore, 2/5*210 = 84 newsletters were addressed during the second hour.
Answer: D.
24 Jan 2014, 05:45
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Newsletters during first hour = 0.25 * 280 = 70. So remaining is 210.
2/5 of 210 = 420/5 = 84. So answer is (D).
2/5 of 210 = 420/5 = 84. So answer is (D).
