NEW HERE? LEARN MORE
closeclose
Last visit was: 24 Apr 2024, 11:11 It is currently 24 Apr 2024, 11:11
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

The table displays the results of a repeated sampling of the Gallus ga

Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Sajjad1994
GRE Forum Moderator
Joined: 02 Nov 2016
Posts: 13958
Own Kudos [?]: 32880 [1]
Given Kudos: 5776
GPA: 3.62
Send PM
CAT Tests Forum Quiz Mode
The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 09:00
1
Bookmarks
Expert Reply
00:00

Difficulty:

45% (medium)

Question Stats:

83% (02:07) correct 17% (02:19) wrong based on 24 sessions
Hide Show timer Statistics
IR Butler Competition 2021 - Participate and Win!
Question # 29, Date : 14-Jan-2021
This question is a part of IR Butler competition 2021. Click here for Details


Genetic SequencePercent of
Samples		CategoryNumber of Amino
Acids in Sequence		Gene Encodes
Protein
Alpha-1-antiproteinase 229A425No
Alpha-1-antitrypsin32A437No
Angiotensinogen24A476No
Heparin cofactor 223D488No
Neuroserpin precursor35I410Yes
Ovalbumin precursor64B386Yes
Ovalbumin-related protein Y99B397No
Plasma protease C1 inhibitor-like27G503No
Protein Z-dependent protease inhibitor31A439No
Serpin B644B379Yes
Serpin H1 precursor33H405Yes


The table displays the results of a repeated sampling of the Gallus gallus (chicken) genome in which 11 genetic sequences were found. The percent of samples in which various sequences were found, as well as the category, number of amino acids, and ability to encode protein for each sequence, is provided.

For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False.

Show Spoiler
Attachment:
2.jpg
2.jpg [ 113.15 KiB | Viewed 3440 times ]
­
True False
The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.
Submit
Click Submit to add this question to your Error log
ShowHide Answer
Official Answer
The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.: False Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.: False When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.: True
Most Helpful Reply
User avatar
L
Sajjad1994
GRE Forum Moderator
Joined: 02 Nov 2016
Posts: 13958
Own Kudos [?]: 32880 [0]
Given Kudos: 5776
GPA: 3.62
Send PM
CAT Tests Forum Quiz Mode
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   15 Jan 2021, 09:30
Expert Reply
Official Explanation

Statement 1: False. Sort the table by Gene Encodes Protein; there are seven “No” sequences. Scan the Percent of Sample column for these seven sequences. Six of them are less than 50%, but Ovalbumin-related protein Y is 99%.

Statement 2: False. Sort the table by Category. The four sequences in category A each have over 400 amino acids. The three sequences in category B each have between 300 and 400 amino acids. Therefore the average number of amino acids is actually higher for the sequences in category A.

Statement 3: True. Sort the table by Number of Amino Acids in Sequence. Of the 11 sequences, 5 have fewer than 415 amino acids; therefore, 6 of the 11 have 415 or more. When choosing one of the 11 sequences at random, there is a 6/11 chance to choose one with more than 415 amino acids. This probability is greater than 1/2.

False, False and True
General Discussion
User avatar
L
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Posts: 3137
Own Kudos [?]: 2769 [0]
Given Kudos: 1510
Location: India
Schools: Cranfield (A) Warwick MiM "23 (M)
GPA: 4
WE:Analyst (Internet and New Media)
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 12:20
1) The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
=> FALSE
Ovalbumin related protein Y can't encode a protein but has 99% of samples taken.

2) Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
=> FALSE
Amino acid average of Category A has an average in the 400 range, whereas the amino acid range of Category B has an average of 300 range.

3) When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.
=> True
6 of the sequences have a greater amino acid count than 415
so the probability is 6/11, which is greater than 1/2
avatar
D
TarunKumar1234
VP
VP
Joined: 14 Jul 2020
Posts: 1139
Own Kudos [?]: 1292 [0]
Given Kudos: 351
Location: India
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 12:38
Given,

The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.-> we can't say it is true of false. Because, there are 4 cases where gene encode protein, in 3 cases samples taken are below 50% (35%, 44% and 33%), but in one case gene encode protein is 64% (greater than 50%). So, we can't say anything for sure here.

Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.- False

Reason:
Average of A = (425+437+476+439)/4= 444.25
Average of B = (386+397+379)/3= 387.3

So, Average of A is not less than Average of B.

When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.- True

Reason:
Event= there are 6 sequences where amino acids is greater than 415 (425, 437,476,488,503 and 439)

P(Event)= 6/11 >1/2
avatar
B
Estate
Intern
Intern
Joined: 18 Jan 2020
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 3
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 14:45
F F T
avatar
G
Deepakjhamb
Manager
Manager
Joined: 29 Mar 2020
Posts: 226
Own Kudos [?]: 126 [0]
Given Kudos: 14
Location: India
Concentration: General Management, Leadership
Schools: HBS '22 IIMA PGPX'22
GPA: 3.96
WE:Business Development (Telecommunications)
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 20:48
For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False.

True False
The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.

solution :

1)The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken :

by observation we see that sequences that cannot encode protein , one of them has been found in 99% SAMPLES ( Ovalbumin realted protein Y) , So clearly this is False

so answer for 1) is FALSE

2)Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B:

By observation we see that Category A sequences are 4 in number and are in 400's while B category sequences are 3 in number and are in 300's , so we do not even need to calculate and can infer that average of A would be greater than B for amino acids , so answer for q2 is also FALSE

3)When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.:

We see that 6 sequences have amino acids > 415
so Prob (Desired ) = 6/11 which will be 1/(1.some decimal) so definitely this will be greater than 1/2

so answer for q3 is True
avatar
B
gauravmanu
Intern
Intern
Joined: 11 Jul 2015
Posts: 43
Own Kudos [?]: 8 [0]
Given Kudos: 12
Location: India
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 22:13
1) False
2) False
3) True
User avatar
G
Sumi1010
Senior Manager
Senior Manager
Joined: 21 Aug 2018
Posts: 308
Own Kudos [?]: 681 [0]
Given Kudos: 19
Location: India
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   14 Jan 2021, 22:55
For each of the following statements, select True if the statement can be verified as true based on the information in the table.

The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken.
-- The sequence Ovalbumin-related Protein Y cannot encode protein, but is found in 99% of the samples taken.
FALSE.
Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.
--This statement is clearly FALSE as each of the sequences in category A have 400+ amino acids while each of the sequences in category B have <400 amino acids.
To be precise -
Total number of amino acids in Sequences in category A = 425 + 437 + 476 + 439 = 1777
Thus, The average number of amino acids in Sequences in category A = 1777/4 = 444.25

Total number of amino acids in Sequences in category B = 386 + 397 + 379 = 1162
Thus, The average number of amino acids in Sequences in category B = 1162/3 = 387.33

FALSE

When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.
The number of sequences having more than 415 amino acids = 6
That is 6 out of 11 ( > 50%) sequences have more than 415 amino acids .

TRUE

Thus, answers are :
FALSE, FALSE, TRUE
avatar
P
rocky620
Retired Moderator
Joined: 10 Nov 2018
Posts: 538
Own Kudos [?]: 436 [0]
Given Kudos: 229
Location: India
Concentration: General Management, Strategy
Schools: IIMA PGPX'22 IIMB EPGP'22 IIMC PGPEX'22 ISB'22
GMAT 1: 590 Q49 V22
WE:Other (Retail)
Send PM
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   15 Jan 2021, 05:07
For each of the following statements, select True if the statement can be verified as true based on the information in the table. Otherwise, select False.

The sequences listed that cannot encode protein were each found in fewer than 50% of the samples taken. False. Ovalbumin-related protein Y cannot be encoded and it was found in 99% of the samples.

Sequences in category A have a lower average (arithmetic mean) number of amino acids than those sequences in category B.False
Sequences in Category A = 425, 437, 476, 439, Mean = 444.25
Sequences in Category B = 386, 397, 379, Mean = 387.33
We do not even have to calculate as the Sequences in category A are all above 420, and those in category B are all below 400. We can infer that the mean of Category A will be greater than that of Category B.

When choosing one of the 11 sequences at random, the probability that the sequence will have more than 415 amino acids is greater than 1/2.True
Sequences which have more than 415 amino acids = 425, 437, 476, 488, 503, 439, Total count = 6
Probability = \(\frac{6}{11}\), which is greater than \(\frac{6}{12}\) or \(\frac{1}{2}\)
User avatar
L
Sajjad1994
GRE Forum Moderator
Joined: 02 Nov 2016
Posts: 13958
Own Kudos [?]: 32880 [0]
Given Kudos: 5776
GPA: 3.62
Send PM
CAT Tests Forum Quiz Mode
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink] New post   15 Jan 2021, 09:17
Expert Reply
This is an Easy question, OA Is False, False and True. Everyone did well here. Official explanation will be posted soon.
GMAT Club Bot
gmatclubot
Re: The table displays the results of a repeated sampling of the Gallus ga [#permalink]
15 Jan 2021, 09:17
Moderators:
Bunuel
Math Expert
92902 posts
BottomJee
DI Forum Moderator
1031 posts
chetan2u
RC & DI Moderator
11169 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions