Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Sep 2807:00 PM EDT
-10:00 PM EDT
Boost your GMAT score in less than one month in a live online class + 6 months access to TTP OnDemand video courses included! Class starts Mon, Tues, Wed, Thur, Fri Sept. 28, 2026 - Oct. 16, 2027, 7:00pm-10:00pm EST
Sep 2911:00 AM EDT
-01:00 PM EDT
" Description: Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Tues/Thur Sept. 29, 2026 - Dec. 3, 2026, 11:00am-1:00pm EST
Oct 0107:00 AM BST
-08:00 AM GMT
Welcome to the GMAT Club's Free Interview Prep Event for Top MBA Programs! Buy tickets - Virtual series that’s all set to equip you to -excel in your MBA interviews.
Oct 0301:00 PM EDT
-04:00 PM EDT
Top scores are possible when you enroll in a powerful GMAT course, taught live online + 6 months access to TTP OnDemand video courses included! Class starts Saturdays Oct. 3, 2026 - Dec. 26, 2026, 1:00pm-4:00pm EST
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
61% (02:50) correct
39%
(02:53)
wrong
based on 1092
sessions
History
Date
Time
Result
Not Attempted Yet
n is an integer greater than or equal to 0. The sequence \(t_n\) for n > 0 is defined as \(t_n = t_{n-1} + n\). Given that \(t_0 = 3\), is tn even?
(1) n + 1 is divisible by 3
(2) n - 1 is divisible by 4
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
(1) n + 1 is divisible by 3
(2) n - 1 is divisible by 4
(A) Statement 1 alone is sufficient, but statement 2 alone is not.
(B) Statement 2 alone is sufficient, but statement 1 alone is not.
(C) Both statements together are sufficient, but neither alone is sufficient.
(D) Each statement alone is sufficient.
(E) Neither statement is sufficient, even when combined.
16 Mar 2011, 02:00
Kudos
Bookmarks
See, t0 is odd.
Then we add an odd number (n=1), so t1 is even.
Then we add an even number(n=2), so t2 is even.
Then we add an odd number (n=3), so t3 is odd.
Then we add an even number(n=4), so t4 is odd.
Then we add an odd number(n=5), so t5 is even.
Then we add an even number(n=6), so t6 is even.
Then we add an odd number(n=7), so t7 is odd.
Then we add an even number(n=8), so t8 is odd.
Etc........
As you could see here the sequence is connected with divisibility by 4.
So (1) tells us about divisibility by 3 and it should be not sufficient. See countrexample: t2 is even (n+1 is 3), t8 is odd (n+1=9)
(2) alone should be sufficient since it tells us about the divisibility by 4, and we see that n which are divided by 4 with remainder of 1 or 2 is even. If the remainder is 0 or 3, it is odd. Here the reminder is 1 (n-1 is divided by 4), so the term should be even.
The answer is (B)
Then we add an odd number (n=1), so t1 is even.
Then we add an even number(n=2), so t2 is even.
Then we add an odd number (n=3), so t3 is odd.
Then we add an even number(n=4), so t4 is odd.
Then we add an odd number(n=5), so t5 is even.
Then we add an even number(n=6), so t6 is even.
Then we add an odd number(n=7), so t7 is odd.
Then we add an even number(n=8), so t8 is odd.
Etc........
As you could see here the sequence is connected with divisibility by 4.
So (1) tells us about divisibility by 3 and it should be not sufficient. See countrexample: t2 is even (n+1 is 3), t8 is odd (n+1=9)
(2) alone should be sufficient since it tells us about the divisibility by 4, and we see that n which are divided by 4 with remainder of 1 or 2 is even. If the remainder is 0 or 3, it is odd. Here the reminder is 1 (n-1 is divided by 4), so the term should be even.
The answer is (B)
16 Mar 2011, 04:57
Kudos
Bookmarks
t0 = 3,
So t1 = t0 + n = 3 + n
t2 = 3 + n + n = 3 + 2n
t3 = 3 + 2n + n = 3 + 3n
So tn is even only if n is odd as odd + odd, if n is even then it will be odd + even = odd
From (1) we have n + 1 is divisible by 3 => n + 1 = 3k where k is an integer.
So n = 3k - 1 which can be values like 2, 5, 8, so (1) is insufficient.
From (2) we have n-1 = 4m where m is an integer
So n = 4m + 1, which is always odd
Hence (2) is sufficient, so the answer is B.
So t1 = t0 + n = 3 + n
t2 = 3 + n + n = 3 + 2n
t3 = 3 + 2n + n = 3 + 3n
So tn is even only if n is odd as odd + odd, if n is even then it will be odd + even = odd
From (1) we have n + 1 is divisible by 3 => n + 1 = 3k where k is an integer.
So n = 3k - 1 which can be values like 2, 5, 8, so (1) is insufficient.
From (2) we have n-1 = 4m where m is an integer
So n = 4m + 1, which is always odd
Hence (2) is sufficient, so the answer is B.
