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yeah! will be reattempting, as i m going to apply for MiM programs.

does someone know which b school i can target with this score for MIM. PS- I am from India :)
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Quote:

*garvitpareek writes:*
does someone know which b school i can target with this score for MIM. PS- I am from India :)
Most german schools, Tier 2 french schools ( Non- ESSEC, HEC, ESCP) are all safe ( Emlyon/ EDHEC etc...)
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garvitpareek
yeah! will be reattempting, as i m going to apply for MiM programs.
It’s a good score for MIM.

garvitpareek
does someone know which b school i can target with this score for MIM. PS- I am from India :)
If you have a good story then you can get into any top b-schools.
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thanks guys for replying.

btw what u do ? have you given GMAT?
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Does anyone know how to solve this problem?
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We can the write the sum of 11 numbers as 50*11=550. Then sum of the first 6 numbers (arranged in ascending order) equals 44*6=264. Subtracting this from the sum of all numbers we get, the sum of the rest 5 numbers = 286. We are also given sum of last 6 numbers is 342. Subtract 286 from 342. You will get 56
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Sum of the 11 numbers is 550
Next sum of smallest 6 numbers will be 264 and that of greatest 6 numbers will be 342..adding both will give sum of the 11 numbers + median number(added extra). Subtract 550 from 606 to get 56
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Does anyone know how to solve this problem?
This question is discussed in detail here: the-average-arithmetic-mean-of-11-numbers-is-50-when-the-numbers-421847.html

Please try searching the forum with the search box. It’s very easy, fast and effective.

Here is a solution:

Firstly, since we are dealing with 11 numbers, which is an odd count, the median will be the middle number when arranged in order. This means the median is the 6th largest number.

Next, given that the average of the 11 numbers is 50, the total sum of these numbers is 11*50 = 550.

We are also given that the average of the 6 smallest numbers is 44 and the average of the 6 greatest numbers is 57. Thus, the sum of the 6 smallest numbers is 6*44, and the sum of the 6 greatest numbers is 6*57. As the 6th largest number is counted in both groups, the combined sum of these two groups is greater than the total sum by exactly the value of the 6th largest number.

Therefore, the 6th largest number equals (6*57 + 6*44) - 550 = 6(57 + 44) - 550 = 6*101 - 550 = 606 - 550 = 56.

Answer: E.
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How representative are GMAT Club full length test to real GMAT exam?
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