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# Nicky and Chadi begin running a race at the same time, though Nicky st

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Math Expert
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Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 02:38
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Difficulty:

15% (low)

Question Stats:

77% (01:25) correct 23% (02:02) wrong based on 96 sessions

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Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run by the time Chadi passes him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds

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Joined: 28 Feb 2020
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 08:44
6
This is another good example of Relative speed.

Their relative speed is 5 - 3 = 2 ms

The distance between them is 36 meters.

We have Speed and Distance, we only need to find time.

T=36/2 = 18 seconds.

A kudos is appreciated.
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 08:49
Bunuel wrote:
Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run by the time Chadi passes him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds

from given info we can say
relative speed = 5-3 ; 2 m/s
and relative time; 36/2 ; 18 sec
so Nicky would have run ; 18+36/3 ; 18+12 ; 30 seconds
IMO D
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 09:00
Archit3110

But they both start at the same time, so why do we need to add the extra time?
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 09:24

[quote="karnavora1"][url=https://gmatclub.com:443/forum/memberlist.php?mode=viewprofile&un=Archit3110][b]Archit3110[/b][/url]

But they both start at the same time, so why do we need to add the extra time?[/quote]

[size=80][b][i]Posted from my mobile device[/i][/b][/size]
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 09:26
Archit3110

It says "Nicky and Chadi begin running a race at the same time"
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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11 Mar 2020, 16:28

Both start at the same time, and the question asks how long has nicky run when Chadi catches her.
at t=0, distance between a and b is 36
at t=18, a catches b

total time passed = 18s
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st  [#permalink]

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22 Jun 2020, 12:14
Bunuel wrote:
Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run by the time Chadi passes him?

(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds

Distance between them = 36
Relative speed= 3-5 = 2

T= D/R

T= 36/2 = 18 B.
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Re: Nicky and Chadi begin running a race at the same time, though Nicky st   [#permalink] 22 Jun 2020, 12:14