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10 Feb 2021, 05:45
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
58% (02:38) correct
42%
(02:17)
wrong
based on 98
sessions
History
Date
Time
Result
Not Attempted Yet
Number of odd integers between 1000 and 8000 which have none of their digit repeated, is
(A) 1736
(B) 1014
(C) 810
(D) 690
(E) 670
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
(A) 1736
(B) 1014
(C) 810
(D) 690
(E) 670
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
10 Feb 2021, 06:09
Kudos
Bookmarks
Bunuel
Contraints:
- They must be 4 digit numbers
- Thousands digit can be any digit from 1 to 7
- They must be 4 digit numbers
- Thousands digit can be any digit from 1 to 7
_ _ _ 4
Right-most place can be filled in 4 ways using {1, 3, 5, 7}
Leftmost place can now be filled in 6 ways (leaving the digit that has been used at units place
6 _ _ 4
Remaining two places can be filled in 8*7 ways (leaving the digit that have been used at units and thousands place
6 * 8 * 7 * 4
Total Numbers = 1344
Now, our answer has to be greater than this because another case with Unit's place as 9 also needs to consider so we have our answer here because only one option has value greater than 1344
Answer: Option A
Answer: Option A
If the unit's digit is filled with digit 9 then total outcomes = 7 * 8 * 7 * 1 = 392
Total Outcomes = 1344+392 = 1736
Answer: Option A
