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21 Nov 2020, 19:07
Kudos
Bookmarks
Table Method is the way to go
Take the total as 100, something that is divisible by all fractions given in the question, so as to solve this without any complicated fractions/calculations.
You will get 20/100 or 1/5 as the answer.
Posted from my mobile device
Take the total as 100, something that is divisible by all fractions given in the question, so as to solve this without any complicated fractions/calculations.
You will get 20/100 or 1/5 as the answer.
Posted from my mobile device
24 Nov 2020, 11:19
Kudos
Bookmarks
msand
Let all student of the dormitory = 120
First-year student = 60
Second year student= 60
Students of first year who declared major \(= (1-\frac{4}{5})=\frac{1}{5}\) \(=60*\frac{1}{5 }= 12\)
Students of the second year who declared major \(= 12*3=36\)
Student of the second year, who didn't declare major \(= 60-36=24\)
\(\frac{second-year \ students \ who \ have \ not \ declared \ a \ major}{Total \ students of \ the \ dormitory} = \frac{24}{120}=\frac{2}{10}=\frac{1}{5}\)
The answer is \(B\)
24 Jan 2021, 17:22
Kudos
Bookmarks
msand
Total Students \(= 60 \)
First year's \(= 30;\) Do not declared major \(=30*\frac{4}{5}=24\), Declared maror \(=6\)
Second year's 30, Declared major 6*3=18, don't declared major \(30-18=12\)
The fraction \(\frac{12}{60}=\frac{1}{5}\)
The answer is B
