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Of the votes cast on a certain proposal, 80 more were in favor of the
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24 Nov 2015, 09:31
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81% (01:51) correct 19% (02:22) wrong based on 100 sessions
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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24 Nov 2015, 09:43
Bunuel wrote: Of the votes cast on a certain proposal, 80 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.)
(A) 480 (B) 400 (C) 300 (D) 240 (E) 160 Solution : Let x be no. of votes against the proposal. Then no. of votes in favor would be x+80 and total no. of votes would be 2x+80. 40%(2X + 80) = X ==> X=160. Total no. of votes = 2(160) + 80 = 400 Option B



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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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24 Nov 2015, 09:48
Let the total number of votes cast = T Number of votes cast in favour of proposal = F Number of votes cast against the proposal = A F = A + 80  1 Since , the number of votes against the proposal was 40 percent of the total vote A= (40/100)*T = .4T  2 => F = (60/100)*T = .6T  3 From equations 1 , 2 and 3 ,we get .2T = 80 => T= 400 Answer B
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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07 Dec 2015, 16:50
Let x be the total of votes cast, the solution we want. Number of people against the proposal: \(\frac{40}{100}\) x Number of people in favor: 1  \(\frac{40}{100}\) x = \(\frac{60}{100}\) x Since, Bunuel wrote: 80 more were in favor of the proposal than were against it that means 80 is the difference of the two percentages. \(\frac{60}{100}\) x  \(\frac{40}{100}\) x = \(\frac{20}{100}\) x \(\frac{20}{100}\) x = 80 x = 400



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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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08 Dec 2015, 00:14
favour of proposal =x+80 against the proposal=x total votes =2x+80 now, .4(2x+80)=x .8x+32=x .2x=320 x=320/2=160=votes against total votes =320+80=400



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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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08 Dec 2015, 16:54
Hi All, This question can be solved by TESTing THE ANSWERS. Under normal circumstances, we would start by TESTing Answer B or D first. Since B is the 'easier' value, we'll start there... Answer B: 400 total votes We're told that 40% of the total votes were votes AGAINST the proposal: (.4)(400) = 160 votes against So the remaining votes were in FAVOR of the proposal: 400  160 = 240 votes for With these two numbers, the difference is 240160 = 80, which is a MATCH for what we were told. Thus, this MUST be the answer. Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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09 Jan 2016, 01:36
Against = x For = x+80
get proportion
x/x+x+80=4/10
10x=8x+320 => x=160, so total number = 160*2+80=400
B



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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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09 Jan 2016, 02:16
Bunuel wrote: Of the votes cast on a certain proposal, 80 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.)
(A) 480 (B) 400 (C) 300 (D) 240 (E) 160 Hi, Although a relatively simpler Question, fast thinking can save time for slightly complex Qs later..IF votes against are 40 %, votes for will be 60%. the difference is 20% which is given as 80.. so total will be 80/20 * 100=400 B
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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23 Jan 2019, 04:15
Bunuel wrote: Of the votes cast on a certain proposal, 80 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.)
(A) 480 (B) 400 (C) 300 (D) 240 (E) 160
\(? = t\left( {{\rm{total}}} \right)\,\,\,\,\left\{ \matrix{ \,{\rm{against}}\,\,\,{\rm{ = }}\,\,a\,\,\mathop = \limits^{{\rm{stem}}} \,\,{2 \over 5}t \hfill \cr \,{\rm{for}}\,\,{\rm{ = }}\,\,t  a\,\,\mathop = \limits^{{\rm{stem}}} \,\,80 + a\,\,\, \Rightarrow 2a = t  80 \hfill \cr} \right.\,\,\,\, \Rightarrow \,\,\,2\left( {{2 \over 5}t} \right) = t  80\,\,\,\, \Rightarrow \,\,\,{1 \over 5}t = 80\,\,\,\, \Rightarrow \,\,\,\left( {\rm{B}} \right)\) We follow the notations and rationale taught in the GMATH method. Regards, Fabio.
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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27 Jan 2019, 18:27
Bunuel wrote: Of the votes cast on a certain proposal, 80 more were in favor of the proposal than were against it. If the number of votes against the proposal was 40 percent of the total vote, what was the total number of votes cast? (Each vote cast was either in favor of the proposal or against it.)
(A) 480 (B) 400 (C) 300 (D) 240 (E) 160 We can let n = the total number of votes. Thus, 0.4n votes were against the proposal, and 0.6n votes were in favor of the proposal. We can create the equation: 0.6n  0.4n = 80 0.2n = 80 n = 80/0.2 = 800/2 = 400 Answer: B
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Re: Of the votes cast on a certain proposal, 80 more were in favor of the
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