Last visit was: 11 Sep 2024, 06:16 It is currently 11 Sep 2024, 06:16
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
Tags:
Difficulty: 805+ Level,   Graphs,               
Show Tags
Hide Tags
Manager
Manager
Joined: 03 Jun 2019
Posts: 220
Own Kudos [?]: 11674 [36]
Given Kudos: 49
Most Helpful Reply
Retired Moderator
Joined: 05 May 2016
Posts: 755
Own Kudos [?]: 710 [6]
Given Kudos: 1316
Location: India
Send PM
General Discussion
Senior Manager
Senior Manager
Joined: 15 Jul 2018
Posts: 348
Own Kudos [?]: 478 [1]
Given Kudos: 94
Send PM
GRE Forum Moderator
Joined: 02 Nov 2016
Posts: 14018
Own Kudos [?]: 38708 [2]
Given Kudos: 5865
GPA: 3.62
Send PM
Re: On Days 1 through 4 of a recent week, Product X was out of stock at [#permalink]
2
Kudos
Expert Reply
Official Explanation

According to the graph and the accompanying text, 25% of the Day 1 shoppers returned on Day 2, and 19% of those shoppers subsequently returned on Day 3. Thus, on Day 3, 100(.25)(.19) = 4.75% of Day 1 shoppers returned to the store.

The correct answer is Between 1 and 10.

Day 1 shoppers who purchased an item in place of Product X paid, on average, 130% of the amount that they would have paid for Product X. According to the graph, 60% of Day 1 shoppers chose to buy an alternative product on Day 1. The total spent by these shoppers, as a fraction of the total all Day 1 shoppers would have spent had each instead bought Product X, is \(\frac{(60)(130)}{(100)(100)} = \frac{7,800}{10,000}\), or 78%.

The correct answer is 78.
Manager
Manager
Joined: 31 Jan 2020
Posts: 228
Own Kudos [?]: 15 [1]
Given Kudos: 139
Send PM
On Days 1 through 4 of a recent week, Product X was out of stock at [#permalink]
1
Kudos
parkhydel wrote:
Attachment:
3.jpg


On Days 1 through 4 of a recent week, Product X was out of stock at Retailer R. Day 1 shoppers are those shoppers who came to Retailer R on Day 1 of that week seeking Product X. For each of the first 3 days of that week, the graph shows the subsequent behavior of all the Day 1 shoppers who came to Retailer R seeking Product X on that day. Shoppers at Retailer R who purchased a different item in lieu of Product X paid an average of 30% more for the item.

From each drop-down menu, select the option that creates the most accurate statement based on the information provided.

1. ____________% of Day 1 shoppers returned to the store on Day 3.

A. Fewer than 1
B. Between 1 and 10
C. More than 10



2. Shoppers at Retailer R who purchased substitute items from other manufacturers on Day 1 paid a total amount that was approximately______________% of the total all Day 1 shoppers would have paid had each of them been able to purchase Product X on Day 1.

A. 60
B. 78
C. 100
D. 130


Dear experts, AndrewN KarishmaB

For the question 1, 1. ____________% of Day 1 shoppers returned to the store on Day 3.

A. Fewer than 1
B. Between 1 and 10
C. More than 10

I understand that on Day 1 there are 25% of the shoppers who return the Day 2 = 25% of 100 = 25.
But we don't how many people in 25% decide to return on Day 3. All of them may not return to Day 3 (0%) or Most of them may return to Day3 (thus, it is possible that No. of Day1 shoppers may be still 25 or greater than 10)­
Tutor
Joined: 21 Mar 2017
Status:Professional GMAT Trainer
Affiliations: GMAT Coach
Posts: 424
Own Kudos [?]: 1360 [4]
Given Kudos: 204
Location: United States (WA)
GMAT 1: 760 Q50 V44
GMAT 2: 770 Q51 V44
GMAT 3: 770 Q50 V44
GMAT 4: 770 Q50 V45 (Online)
GMAT 5: 780 Q51 V48
Send PM
Re: On Days 1 through 4 of a recent week, Product X was out of stock at [#permalink]
4
Kudos
Expert Reply
­Tougher one!

If we read with precision and stay organized, then the calculations are pretty quick.

Video solution here: 




 
Intern
Intern
Joined: 15 Jul 2018
Posts: 11
Own Kudos [?]: 0 [0]
Given Kudos: 19
Send PM
Re: On Days 1 through 4 of a recent week, Product X was out of stock at [#permalink]
For blank 1, the question is asking what percentage of the people on Day1, who did not make a purchase, returned the next day, retuned on day 2 but still did not make a purchase, retuned the next day.
Let s be the total number of shoppers on Day 1.
25% did not make a purchase, retuned the next day- 0.25x
On day 2,
19% still did not make a purchase and returned the next day ie out of 0.25x 19% retuned on day 3. 0.25x * 0.19 ~0.05x. Since the answer is a percentage, it will be ~5% so between 1 and 10.

For blank 2, the question is asking the percentage of the amount spent by 60% of the people in Day 1 in comparison to the amount that all the people on day1 would have spent had product X been available.
The cost of different item is 1.3 times product X.
Let the cost of product X be c and the total number of shoppers on day 1 be s.
The percentage = 0.6*1.3*cs/cs = 0.78*100= 78%
GMAT Club Bot
Re: On Days 1 through 4 of a recent week, Product X was out of stock at [#permalink]
Moderators:
Math Expert
95450 posts
Retired Moderator
997 posts
RC & DI Moderator
11513 posts